Explanation:
Given Data
Total mass=93.5 kg
Rock mass=0.310 kg
Initially wagon speed=0.540 m/s
rock speed=16.5 m/s
To Find
The speed of the wagon
Solution
As the wagon rolls, momentum is given as
P=mv
where
m is mass
v is speed
put the values
P=93.5kg × 0.540 m/s
P =50.49 kg×m/s
Now we have to find the momentum of rock
momentum of rock = mv
momentum of rock = (0.310kg)×(16.5 m/s)
momentum of rock =5.115 kg×m/s
From the conservation of momentum we can find the wagons momentum So
wagon momentum=50.49 -5.115 = 45.375 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
Speed of wagon=45.375/(93.5-0.310)
Speed of wagon= 0.487 m/s
Throwing rock backward,
momentum of wagon = 50.49+5.115 = 55.605 kg×m/s
Speed of wagon = wagon momentum/(total mass-rock mass)
speed of wagon = 55.605 kg×m/s/(93.5kg-0.310kg)
speed of wagon= 0.5967 m/s
I believe it’s the mass of the box but I don’t no if I’m right
Hope this helped
I claim that it's d moving electrons.
As the gas cools down, particle movement slows down with it, and so does the temperature of the gas. This is because the more heat or thermal energy a gas has, the faster the particles move. This is why absolute zero, or 0 degrees Kelvin is defined as zero particle movement, because it has zero energy.
Hope this helps
For the electric field is measured for points at distances r,Electric field is mathematically given as
E=19.9*10^{-5}c/m^3
<h3>What is the
Electric field?</h3>
Generally, the equation for the electric field uniform charged is mathematically given as

Therefore
E=lr/3E0=3Ee0/r
Therefore
E=3*6*10^4*8.85*10^{-12}
E=19.9*10^{-5}c/m^3
In conclusion, E=19.9*10^{-5}c/m^3
E=19.9*10^{-5}c/m^3
Read more about Electric field
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CQ
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