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2 years ago

How do storms on Jupiter differ from storm systems on Earth?

Physics

1 answer:

Vladimir [108]2 years ago

8 0

Answer:

As, Jupiter are one of the largest planet in the solar system and the large amount of the mass of the jupiter are consisted with the gases. The storm tracks in the symmetrical path at the proper latitude in the system. But the storm tracks on the earth in the system where planet are highly variable.

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In this image of Earth and the Moon from the Sim, what does the circle around Earth represent?

lidiya [134]

Answer: This is the orbit (of the moon around Earth).

An orbit is a circular/oval path that planets, moons, comets, etc follow with a "subject" in the middle. In this case, the circle is the orbit of the moon around Earth.

5 0

3 years ago

Tyrone, an 85-kg teenager, runs off the end of a horizontal pier and lands on a free-floating 130-kg raft that was initially at

Ghella [55]

Answer:u=4.04 m/s

Explanation:

Given

Mass m=85 kg

mass of Raft M=130 kg

velocity of raft and man v=1.6 m/s

Let initial speed of Tyrone is u

Conserving Momentum as there is no external Force

$mu=(M+m)v$

$85\times u=(85+130)\cdot 1.6$

$u=\frac{215}{85}\cdot 1.6$

$u=2.529\cdot 1.6=4.04 m/s$

4 0

3 years ago

A gun is fired on a day when the speed of sound is 335 m/s and an echo is heard 0.75 seconds later. How far away is the object t

cricket20 [7]

Answer:

v= 335 m/s

2∆t= 0.75 s

∆x= v.∆t → ∆x= 335×½×0.75 = 125.625 m

8 0

2 years ago

What makes up (composition) of alpha particle

Pavlova-9 [17]

Alpha particles are composite particles consisting of two protons and two neutrons tightly bound together.

(not much explanation, I hope this is what you were looking for!)

5 0

3 years ago

A 50.1 kg diver steps off a diving board and drops straight down into the water. The water provides an average net force of resi

Varvara68 [4.7K]

Answer:

The total distance is 16.9 m

Explanation:

We understand work in physics as certain force exerted through certain distance. To reach that point below the water, the work done by the diver must be equal to the work done by the water's force of resistance. Therefore, we determine both work expressions and we solve the equation for the diver distance, which is the total distance between the diving board and the stopping point underwater.

$W_{d}: work done by diver\\W_{R}: work due the force of resistance\\W_{d} = W_{R}\\F_{d}\times d_{d}=F_R \times d_{R}\\d_{d}= \frac{F_R \times d_R}{F_d}= \frac{F_R \times d_R}{m_d \times g}= \frac {1598 N \times 5.2 m}{50.1 kg \times 9.81 m/s^2}\\d_{d}= 16. 91 m$

7 0

2 years ago