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Snowcat [4.5K]
3 years ago
9

URGENT HELP PLS

Physics
1 answer:
Andre45 [30]3 years ago
8 0

Answer:constant amount of work is done

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A. They are a solid.

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2 years ago
if the vessel in the sample problem accelerates fir 1.00 min, what will its speed be after that minute ?
LUCKY_DIMON [66]

Answers:

a) 154.08 m/s=554.68 km/h

b) 108 m/s=388.8 km/h

Explanation:

<u>The complete question is written below: </u>

<u></u>

<em>In 1977 off the coast of Australia, the fastest speed by a vessel on the water was achieved. If this vessel were to undergo an average acceleration of 1.80 m/s^{2}, it would go from rest to its top speed in 85.6 s.  </em>

<em>a) What was the speed of the vessel? </em>

<em> </em>

<em>b) If the vessel in the sample problem accelerates for 1.00 min, what will its speed be after that minute? </em>

<em></em>

<em>Calculate the answers in both meters per second and kilometers per hour</em>

<em></em>

a) The average acceleration a_{av} is expressed as:

a_{av}=\frac{\Delta V}{\Delta t}=\frac{V-V_{o}}{\Delta t} (1)

Where:

a_{av}=1.80 m/s^{2}

\Delta V is the variation of velocity in a given time \Delta t, which is the difference between the final velocity V and the initial velocity V_{o}=0 (because it starts from rest).

\Delta t=85.6 s

Isolating V from (1):

V=a_{av}\Delta t + V_{o} (2)

V=(1.80 m/s^{2})(85.6 s) + 0 m/s (3)

V=154.08 \frac{m}{s} (4)

If 1 km=1000m and 1 h=3600 s then:

V=154.08 \frac{m}{s}=554.68 \frac{km}{h} (4)

b) Now we need to find the final velocity when \Delta t=1 min=60 s:

<em></em>

V=(1.80 m/s^{2})(60 s) + 0 m/s (5)

V=108 \frac{m}{s}=388.8 \frac{km}{h} (6)

5 0
3 years ago
The speed of light inside a medium is (2.0 x 10^8m/s) What is the index of refraction (n) of the medium?
kondor19780726 [428]

Answer:

Refractive index of a medium = Speed of light in vacuum/Speed of light in a medium

1.5 = 3 x 108 / Speed of light in medium

Speed of light in the medium = 3 x 108 /1.5

= 2 x 108 m/s.

Explanation:

3 0
2 years ago
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