Planetary nebulae are characterized by an emission spectrum consisting of Balmer (hydrogen) emission lines and a pair of strong
1 answer:
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(a) 273.9 V
The power rating of the resistor is given by
where
P is the power rating
V is the potential difference across the resistor
R is the resistance
If the maximum power rating is , and the resistance of the resistor is
, then we can find the maximum potential difference across the resistor by re-arranging the previous equation for V:
(b) 1.6 W
In this case, we have:
is the resistance of the resistor
is the potential difference across the resistor
So we can find the power rating by using the same formula of part (a):
(c) Maximum voltage: 14.1 V; Rate of heat: 2.00 W and 3.00 W
Here we have two resistors of
and each resistor has a power rating of
P = 2.00 W
So the greatest potential difference allowed in the first resistor is
While the greatest potential difference allowed in the second resistor is
So the greatest potential difference allowed not to overheat either of the resistor is 14.1 V.
In this condition, the power dissipated on the first resistor is 2.00 W, while the power dissipated on the second resistor is
And this corresponds to the rate of heat generated in the first resistor (2.00 W) and in the second resistor (1.33 W).
The final temperature is 83 K.
<u>Explanation</u>:
For an adiabatic process,
Given:-
(the gas is monoatomic)
T = 275 0.30
T = 83 K.
Answer:
The wavelength of the wave is
Explanation:
Lets calculate
We know an electromagnetic wave is propagating through an insulating magnetic material of dielectric constant K and relative permeability ,then the speed of the wave in this dielectric medium is
is less than the speed of the light c and is given by a relation
--------- 1
In case the electromagnetic wave propagating through the insulating magnetic material , the amplitudes of electric and magnetic fields are related as -
The magnitude of the 'time averaged value' of the pointing vector is called the intensity of the wave and is given by a relation
----------- 3
now , we will find the speed of the propagation of an electromagnetic wave by using equation 1
Putting the values ,
=
=
=
Now , using this above solution , we will find the wavelength of the wave -
Putting the values from above equations -
Hence , the answer is