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kolezko [41]
3 years ago
10

a road rises 16 feet for every 50 feet of horizontal distance covered. in percent what is the grade of the road?

Mathematics
1 answer:
weeeeeb [17]3 years ago
4 0

Answer:

32%

Step-by-step explanation:

The slope of the road is measured as

slope = \frac{rise}{run} = \frac{16}{50}

To express as a percentage multiply the fraction y 100% , that is

slope = \frac{16}{50} × 100% = 16 × 2 = 32%

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Answer:

B(2,3),C(2,-3)

Step-by-step explanation:

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3 years ago
What's the median of these numbers:<br> 14,20,24,16,20,18
faltersainse [42]
The answer to this is 19. The reason why is because the median falls between 18 and 20. After that, you have to take the middle number that falls between 18 and 20. In this case, 19. 
4 0
3 years ago
Read 2 more answers
The length of a rectangle is 5 metres less than twice the breadth. If the perimeter is 50 meters,find the length and breadth
MAXImum [283]
<h3><u>S</u><u> </u><u>O</u><u> </u><u>L</u><u> </u><u>U</u><u> </u><u>T</u><u> </u><u>I</u><u> </u><u>O</u><u> </u><u>N</u><u> </u><u>:</u></h3>

As per the given question, it is stated that the length of a rectangle is 5 m less than twice the breadth.

Assumption : Let us assume the length as "l" and width as "b". So,

\twoheadrightarrow \quad\sf{ Length =2(Width)-5}

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

Also, we are given that the perimeter of the rectangle is 50 m. Basically, we need to apply here the formula of perimeter of rectangle which will act as a linear equation here.

\\ \twoheadrightarrow \quad\sf{ Perimeter_{(Rectangle)} = 2(\ell +b) } \\

  • <em>l</em> denotes length
  • <em>b</em> denotes breadth

\\ \twoheadrightarrow \quad\sf{50= 2(2b-5+b)} \\

\\ \twoheadrightarrow \quad\sf{50= 2(3b-5)} \\

\\ \twoheadrightarrow \quad\sf{50= 6b - 10} \\

\\ \twoheadrightarrow \quad\sf{50+10= 6b} \\

\\ \twoheadrightarrow \quad\sf{60= 6b} \\

\\ \twoheadrightarrow \quad\sf{\cancel{\dfrac{60}{6}}=b} \\

\\ \twoheadrightarrow \quad\underline{\bf{10\; m = Width }} \\

Now, finding the length. According to the question,

\twoheadrightarrow \quad\sf{ \ell=(2b-5) \; m}

\twoheadrightarrow \quad\sf{ \ell=2(10)-5\; m}

\twoheadrightarrow \quad\sf{ \ell=20-5\; m}

\\ \twoheadrightarrow \quad\underline{\bf{15\; m = Length }} \\

<u>Therefore</u><u>,</u><u> </u><u>length</u><u> </u><u>and</u><u> </u><u>breadth</u><u> </u><u>of</u><u> </u><u>the</u><u> </u><u>r</u><u>ectangle</u><u> </u><u>is</u><u> </u><u>1</u><u>5</u><u> </u><u>m</u><u> </u><u>and</u><u> </u><u>10</u><u> </u><u>m</u><u>.</u><u> </u>

7 0
3 years ago
If KLMN is a parallelogram and<br> m∠K = 110°, then what is m∠L?
dlinn [17]

Answer:

70 degrees

Step-by-step explanation:

In the parallelogram  KLMN, the sum of the adjacent angle is 180 degrees

Hence;

m<K + m<L = 180

110 + m<L = 180

m<L = 180-110

m<L = 70degrees

Hence the measure of m<l is 70 degrees

5 0
3 years ago
In a game, you toss a fair coin and a fair six-sided die. If you toss a heads on the coin and roll either a 3 or a 6 on the die,
pochemuha

Using probabilities, it is found that the expected profit of one round of this game is of $0.

A probability is the <u>number of desired outcomes divided by the number of total outcomes</u>.

  • One of the two sides of the coin are heads.
  • 2 of the 6 sides of the dice are 3 or 6.

Hence, since the coin and the dice are independent, the <em>probability </em>of winning is:

p = \frac{1}{2} \times \frac{2}{6} = \frac{1}{6}

The expected value is the <u>sum of each outcome multiplied by its respective probability</u>.

In this problem:

  • \frac{1}{6} probability of earning $30.
  • \frac{5}{6} probability of losing $6.

Then:

E(X) = 30\frac{1}{6} - 6\frac{5}{6} = 5 - 5 = 0

The expected profit of one round of this game is of $0.

A similar problem is given at brainly.com/question/24855677

5 0
2 years ago
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