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sammy [17]
3 years ago
14

JK is formed by J(-12,3) and K(8,-5). If line r is the perpendicular bisector of JK, write an equation for r in slope-intercept

form.
Mathematics
1 answer:
dem82 [27]3 years ago
3 0

Answer:

  • y = 5/2x + 4

Step-by-step explanation:

<u>Midpoint of JK:</u>

  • x = (-12 + 8)/2 = -4/2 = -2
  • y = (3 - 5)/2 = -2/2 = -1

<u>Slope of the line JK:</u>

  • m = (-5 - 3)/(8 - (-12)) = -8/20 = -2/5

Perpendicular lines have negative reciprocal slopes.

So the line r has a slope 5/2 and passes through the point (-2, -1)

<u>Equation of r:</u>

  • y = 5/2x + b
  • -1 = 5/2(-2) + b
  • -1 = -5 + b
  • b = 5 - 1
  • b = 4

<u>So the equation is:</u>

  • y = 5/2x + 4
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