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Alenkasestr [34]
3 years ago
15

How do u make y=4x into standard form

Mathematics
1 answer:
Norma-Jean [14]3 years ago
5 0
-4x+y=0
(Using Ax+By=C)
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What interval notation represents the data graphed below?
Aliun [14]

Answer: Choice D

(-\infty, -2) \cup [4, \infty)

=====================================================

Explanation:

The left portion is the interval (-∞, -2)

This is a shorthand way of saying -\infty < x < -2

The curved parenthesis says "do not include this endpoint as part of the solution set". Note the open hole at x = -2 in the diagram.

In contrast, the value x = 4 is included (due to the filled in circle), so we use a square bracket for this endpoint. Therefore, the right-hand portion is represented by [4, ∞) which translates to 4 \le x < \infty

Negative and positive infinity will always use a parenthesis, and never a square bracket. This is because we can only approach infinity but never reach it, so we cannot include it as an endpoint.

All of this builds up to the full interval notation to be (-\infty, -2) \cup [4, \infty)

The only square bracket is near the 4; everything else is a curved parenthesis. This is why choice D is the final answer.

6 0
3 years ago
If the subtrahend is 9 and the difference is 8 what is the minuend
enyata [817]
The subtrahend is 9 and the difference is 8 and the minuend is 17
3 0
3 years ago
Use the method of ELIMINATION to solve the system. You must SHOW ALL WORK. Make sure you have an answer for both x and y.
jekas [21]

Answer:

<h3>Required <u>Answer</u><u>:</u><u>-</u></h3>

\sf 4x+8y=10\dots\dots (1)

\sf -4x+2y=-30\dots\dots (2)

  • by adding eq (1) and eq (2) we get

{:}\longrightarrow\sf 4x+8y=20

{:}\longrightarrow\sf -4x+2y=-30

<h2>__________________________</h2>

{:}\longrightarrow\sf 10y=-10

{:}\longrightarrow\sf y={\dfrac {-10}{10}}

{:}\longrightarrow{\underline{\boxed{\bf y=-1}}}

  • Substitute the value in eq (2)

{:}\longrightarrow\sf -4x+2 (-1)=-30

{:}\longrightarrow\sf -4x-2=-30

{:}\longrightarrow\sf -4x=-30+2

{:}\longrightarrow\sf -4x=-28

{:}\longrightarrow\sf x={\dfrac {-28}{-4}}

{:}\longrightarrow{\underline{\boxed{\bf x=7}}}

\therefore{\underline{\boxed{\bf (x,y)=(7,-1)}}}

6 0
3 years ago
Read 2 more answers
I need help on this, if anyone knows how to do this can you help me out pls
ASHA 777 [7]
<h3>Answer:  (3, 0)</h3>

=================================================

Explanation:

Let's isolate x in the first equation.

x-2y = 3

x = 3+2y

Then we'll plug this into the second equation

Afterwards, solve for y.

2x + 4y = 6

2(3+2y)+4y = 6

6+4y+4y = 6

8y+6 = 6

8y = 6-6

8y = 0

y = 0/8

y = 0

Use this to find x.

x = 3+2y

x = 3+2(0)

x = 3

The solution is therefore (x,y) = (3, 0)

If you were to graph both lines, then they would intersect at the location (3,0).

-----------------------------

Checking the answer:

Plug x = 3 and y = 0 into the first equation.

x-2y = 3

3-2(0) = 3

3 - 0 = 3

3 = 3 that works

Repeat for the other equation

2x+4y = 6

2(3) + 4(0) = 6

6 + 0 = 6

6 = 6 that works as well

Both equations are true when (x,y) = (3,0).

The solution is confirmed.

6 0
3 years ago
How do you solve u=xk-y for x
Lynna [10]

u-y = xk

(u-y)÷k = x

This is the answer.

5 0
3 years ago
Read 2 more answers
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