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3 years ago

7

2 6-2___ help please 7 (30points)

2 answers:

serg [7]3 years ago

8 0

6 - 2 2/7 =
6 - 16/7 =
42/7 - 16/7 =
26/7 or 3 5/7

omeli [17]3 years ago

7 0

the answer for ur question is
6-2 2/7=
6- 16/7=
42/7-16/7 = 26/7
26/7 in mixed fraction we can write it as 3 5/7
so 26/7 or 3 5/7 is the answer

HOPE THIS HELPS !!!!

^_^ HAPPY TO HELP U

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How many pounds of a 15% copper alloy must be mixed with 700lb of a 30% copper alloy to maybe a 25.5% copper alloy

lisov135 [29]

Answer:

$300\; \rm lb$ .

Step-by-step explanation:

Let $x$ represent the mass (in pounds) of that $15\%$ copper alloy required, such that the final mixture would contain $25.5\%$ copper by mass.

Consider: if $x$ pounds of that $15\%$ copper alloy is mixed with $700$ pounds that $30\%$ copper alloy, what would be the mass of copper in the mixture?

Mass of copper in $x$ pounds of that $15\%$ copper alloy: $(0.15\, x)\; \rm lb$ .
Mass of copper in $700$ pounds of that $30\%$ copper alloy: $700 \times 0.30 = 210\; \rm lb$ .

Therefore, the mixture would contain $(210 + 0.15\, x) \; \rm lb$ of copper.

The mass of that mixture would be $(700 + x)\; \rm lb$ . The mass fraction of copper in that mixture would be:

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\%$ .

This ratio is supposed to be equal to $25.5\%$ . These two pieces of equations combine to give an equation about $x$ :

$\displaystyle \frac{(210 + 0.15\, x)\; \rm lb}{(700 + x)\; \rm lb} \times 100\% = 25.5\%$ .

$\displaystyle \frac{210 + 0.15\, x}{700 + x} = 0.255$ .

Simplify and solve for $x$ :

$210 + 0.15\, x= 0.255\, (700 + x)$ .

$(0.255 - 0.15)\, x= 210 - 0.255 \times 700$ .

$\displaystyle x = \frac{210 - 0.255 \times 700}{0.255 - 0.15} = 300$ .

Therefore, $300\; \rm lb$ of that $15\%$ alloy would be required.

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timama [110]

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Step-by-step explanation:

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2 years ago

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kicyunya [14]

Answer:

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Step-by-step explanation:

(2g+21) + (2g-6)=191

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2g+21+2g-6 =191

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Gre4nikov [31]

Answer:

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Step-by-step explanation:

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