What is the equation of the line that passes through (0, 2) and (-3, 14) in slope-intercept

1 answer:

6 0

Answer: y=-4x+2

Why: Find slope— 2-14/0+3 = -12/3 = -4

First put it in slope point form
y-2=-4(x-0)

Simplify
y-2=-4x

So...
y=-4x+2

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Find the work done by a force of 4 pounds acting in the direction of 41° to the horizontal in moving an object 5 feet from (0, 0

babymother [125]

F = 5 p
d = 5 ft
The work formula:
W = F * d
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Answer:

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denpristay [2]

Answer:

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Step-by-step explanation:

A perpendicular line has a slope that is the negative reciprocal of that of the given line. When the equation starts out in standard form, a line with negative reciprocal slope can be written by swapping the x- and y-coefficients and negating one of them.

The given x- and y-coefficients have the ratio 1:-3, so we can use the coefficients 3 and 1 for our purpose.

The usual process of making the line go through a given point can be used. That is, we can translate the line from the origin to the desired point by subtracting the point coordinates from x and y. Then we have ...

3(x+3) +(y-5) = 0

This is "an" equation. It is in no particularly recognizable form. It can be rearranged to the form y = mx + b:

3x +9 +y -5 = 0 . . . . . eliminate parentheses

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