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SashulF [63]
3 years ago
12

I WILL BRAINLIEST !!!

Mathematics
1 answer:
olya-2409 [2.1K]3 years ago
6 0

Answer:  11/18

=======================================================

Explanation:

We need to add the fractions, but first we need to get each fraction to have the LCD (lowest common denominator) of 18

18 is the LCM of the denominators 6 and 9

The fraction 1/6 turns into 3/18 when multiplying top and bottom by 3

The fraction 4/9 turns into 8/18 after multiplying top and bottom by 2

Therefore,

(1/6) + (4/9) = (3/18) + (8/18) = (3+8)/18 = 11/18

So Mike has a total of 11/18 of a gallon of paint when combining the two given amounts 1/6 a gallon of blue paint and 4/9 of a gallon of green paint.

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The graph below shows the relationship between the number of months different students practiced boxing and the number of matche
yulyashka [42]

Part A: The y-intercept of the line of best fit is about 4. This represents the starting point, or figure 0.

Part B: Using the line, you could determine that the slope is about 3/2, or 1.5, and the 13th month would be at about 24 matches.

Equation: y=4x+1.5

Hope this helps,

LaciaMelodii :)

5 0
4 years ago
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The recommended density of a rectangular aquarium is 7 fish per cubic foot of water. If the owner of the aquarium follows the re
TiliK225 [7]

Answer: 2 feets

Step-by-step explanation:

Recommended density = 7 fish/ ft^3

If recommended density guideline is followed:

Number of fishes in aquarium = 42

Length of aquarium = 3ft

Width = 1ft

Height =?

Volume of aquarium = Length × width × height

Volume = 3 × 1 × h = (3ft^2 × h)

Therefore ;

If

1ft^3 = 7 fishes

x ft^3 = 42 fishes

Cross multiply

7(x)ft^3 = 42 fishes

x ft^3 = (42÷7)

x ft^3 = 6

Therefore volume of the aquarium with 42 fishes is 6ft^3

Volume = (3ft^2 × h)

6ft^3 = 3ft^2 × h

h = (6ft^3) / (3ft^2)

h = 2ft

6 0
3 years ago
How to write as a percent <br> 3/5
igomit [66]
60 percent because 3/5= 0.6 and multiply by 100 its 60
8 0
3 years ago
Square roots in trigonometry. I don’t understand please help?
cupoosta [38]

By definitions of the (co)tangent and cosecant function,

3\tan^2x-2=\csc^2x-\cot^2x\iff3\dfrac{\sin^2x}{\cos^2x}-2=\dfrac1{\sin^2x}-\dfrac{\cos^2x}{\sin^2x}

Turn everything into fractions with common denominators:

\dfrac{3\sin^2x-2\cos^2x}{\cos^2x}=\dfrac{1-\cos^2x}{\sin^2x}

Recall that \cos^2x+\sin^2x=1, so we can simplify both sides a bit.

On the left:

\dfrac{3\sin^2x+3\cos^2x-5\cos^2x}{\cos^2x}=\dfrac{3-5\cos^2x}{\cos^2x}

On the right:

\dfrac{1-\cos^2x}{\sin^2x}=\dfrac{\sin^2x}{\sin^2x}=1

(as long as \sin x\neq 0, which happens in the interval 0\le x\le\pi when x=0 or x=\pi)

So we have

\dfrac{3-5\cos^2x}{\cos^2x}=1\implies3-5\cos^2x=\cos^2x

\implies3=6\cos^2x

\implies\cos^2x=\dfrac12

\implies\cos x=\pm\dfrac1{\sqrt2}

\implies x=\dfrac\pi4\text{ or }x=\dfrac{3\pi}4

4 0
3 years ago
The difference between two numbers is 5 if the product is -6​
Zinaida [17]

Answer:

-6

Step-by-step explanation:

4 0
3 years ago
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