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maksim [4K]
3 years ago
13

What is the area of this rectangle? *

Mathematics
2 answers:
Neporo4naja [7]3 years ago
3 0

Answer:

36

Step-by-step explanation:9*4=36

Lemur [1.5K]3 years ago
3 0

Answer:

36

Step-by-step explanation:

9 times 4

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A circular table top has a diameter of 90cm. Work out the area of the table top.
Reptile [31]

Answer:

Find the area of table top( circle)

A=πd²/4

A = 3.1415× (90cm)²/4

A= 3.1415× 8100cm²/4

A= 3.1415×2025

A=6361.5375cm²

The area of the table top is 6361.5375cm².

4 0
2 years ago
Read 2 more answers
Draw an area model that demonstrates that the quotient of 2080 and 40 is 52.
Scrat [10]

Area model is used to illustrate multiplication and division operations.

See attachment for the area model

The equation can be represented as:

\frac{2080}{40} = 52

Express 2080 as 1200 + 800 + 80

\frac{1200 + 800 + 80}{40}=52

Express as

\frac{1200 + 800 + 80}{40}=\frac{1200}{40} + \frac{800}{40} + \frac{80}{40}

Divide

\frac{1200 + 800 + 80}{40}= 30 + 20 + 2

See attachment for the area model

Read more about area models at:

brainly.com/question/18533236

7 0
2 years ago
Peanuts in bulk bins at the grocery store cost $0.30 per ounce.How much would 2 pounds of peanuts cost?
Svetach [21]
1 pound is 16 ounces so multiply by .30 to get 4.80 times 2 bc theres 2 pounds which will be $9.60
5 0
3 years ago
Please Help! Look at attachments.
marshall27 [118]

Answer:

the answer is D.

Step-by-step explanation:

4 0
3 years ago
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If t a n squared θ = 3 /8 , what is the value of  s e c θ
TEA [102]

We can use 3 facts:

\tan{\theta}=\frac{y}{x}

\sec{\theta}=\frac{r}{x}

x^2+y^2=r^2

So, to find our x and our y we can do:

\tan^2{\theta}=\frac{3}{8} \implies \\ \tan{\theta}=\pm{\sqrt{\frac{3}{8}}=\pm\frac{\sqrt{3}}{\sqrt{8}}So, now that we know our x and our y we can find our r.

(\sqrt{3})^2+(\sqrt{8})^2=11 \implies r=\sqrt{11}

You'll notice, though, that there were two solutions for \tan{\theta}, which means we have a positive and a negative for our x. So:

\sec{\theta}=\frac{\sqrt{11}}{\sqrt{8}} \\ \sec{\theta}=-\frac{\sqrt{11}}{\sqrt{8}}}\\ \text{Rationalizing both of them:}\\ \sec{\theta}=\frac{\sqrt{88}}{8} \\ \sec{\theta}=-\frac{\sqrt{88}}{8}

7 0
3 years ago
Read 2 more answers
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