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Answer:
Work done in stretching the spring = 7.56 lb-ft.
Step-by-step explanation:
Normal length of the spring = 8 in or ft
= ft
If the spring has been stretched to 11 inch then the stretched length of the spring is = 11 in
= ft
Force applied to stretch the spring = 12 lb
By Hook's law,
F = kx [where k is the spring constant and x = length by which the spring is stretched]
12 = k()
k = 18
Work done (W) to stretch the spring by ft will be
W =
=
=
= 9()²
= 7.56 lb-ft
The percent of the increase is
I is the increasing value
N is the new value
O is the original value
The price of the cooler is $28.50, then
O = 28.50
The selling price of the cooler is $40.76, then
N = 40.76
We will substitute them in the rule above to find I
Let us calculate it
I = 43.0175 %
Round it to the nearest percent
I = 43%
The answer is D