Answer:
the three consecutive odd integers are 9, 11, and 13.
Step-by-step explanation:
Let's say that the first odd integer is x. The second consecutive odd integer would have to be x+2. (It would not be x+1 because that would result in an even integer. The sum of any two odd numbers is even.) The third consecutive odd integer would be (x+2) +2 or x+4.
The sum of the first, twice the second, and three times the third can be written as:
x+2(x+2)+3(x+4)
This equals 70. We can now distribute and solve for x:
x+2(x+2)+3(x+4)=70
x+2x+4+3x+12=70(distribute)
6x+16=70(combine like terms)
6x=54(subtract 16 from both sides)
x=9(divide by 9)
Thus, the three consecutive odd integers are 9, 11, and 13
hope this helps :)
Answer:
4p+28 - (2p-6)
4p+28 -2p + 6
2p +34
p+17
Step-by-step explanation:
Answer: $1795.42
Step-by-step explanation:
A = 1500
r = 3%
n = 12
t = 6
A = $1795.42
To determine the equation that would be perpendicular with a certain line, we must first know the characteristics of a perpendicular line. This line would have a 90 degrees angle with another line so that the slope of this line would be the negative reciprocal of the slope of the other line. To write the equation, given a certain point we use the point-slope form of a line, y -y1 = m(x - x1).
Original line: <span>-x + 5y= 14
y = x/5 + 14/5
slope = 1/5
Perpendicular line's slope = -5
y - y1 = m (x - x1)
</span> y - (-2) = -5 (x - (-5))
y = -5x - 25 -2
y = -5x -27