Answer: 70,000
Step-by-step explanation:
Answer:
Step-by-step explanation:
Angles 153 and QRP are straight angles, and thus Angle QRP is
180 - 153, or 27 degrees.
The interior angles of the triangle must sum up to 180 degrees:
27 + (3y + 5) + (2y - 7) = 180.
combining like terms, we get:
5y - 25 = 180, or 5y = 155, or y = 31
Then Angle Q is 3(31) + 5, or 93
Angle P is 2(31) - 7, or 55, and
Angle QRP is 27 degrees (found earlier).
Answer:
Not Similer
Step-by-step explanation:
we can use the process of elimination, first AA isn't it because the corresponding angles arn't equal, next SSS itsn't it because we don't know the side lengths, and lastly SAS isn't it because we still don't know the side lengths.
I'll explain how to do the first one:-
y = cos-1(x2)
This can be described as ' a function of a function' x^2 is a function of x and cos-1(x^2) is a function of x^2.
We need to apply the chain rule.
Personally I find this easier to understand if i let u = x^2, so
If y = f(u) and u is a function of x then
dy/dx = dy/ du * du/dx
Here u = x^2 and y = cos-1(u)
du/dx = 2x
so dy/dx = d(cos-1(x^2) dx = dy/du * du/dx
= -1 / √(1 - u^2) * 2x
= -2x / √(1 - u^2)
= -2x / √(1 - (x^2)^2)
= -2x / √(1 - x^4)
I hope this helps. but if not. you might like to employ the formulae in the question - The square boxes contain the 'u' s in my answer. These formulae are equivalent to my explanation.
The given equation, x.cosec²x = cot x - d/dx x.cot x, is proved using the product rule of differentials.
In the question, we are asked to show that x.cosec²x = cot x - d/dx x.cot x.
To prove, we go by the right-hand side of the equation:
cot x - d/dx x.cot x.
We solve the differential d/dx using the product rule, according to which, d/dx uv = u. d/dx(v) + v. d/dx(u), where u and v are functions of x.
cot x - {x. d/dx(cot x) + cot x. d/dx(x)}
= cot x - {x. (-cosec²x) + cot x} {Since, d/dx(cot x) = -cosec²x, and d/dx(x) = 1}
= cot x + x. cosec²x - cot x
= x. cosec²x
= The left-hand side of the equation.
Thus, the given equation, x.cosec²x = cot x - d/dx x.cot x, is proved using the product rule of differentials.
Learn more about differentials at
brainly.com/question/14830750
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