The polynomial is (mx^3+3)(2x²+5x+2)-(8x^5 +20x^4)
if it is reduced to 8x^3+6x²+15x+6, so we can find the value of m
(mx^3+3)(2x²+5x+2)-(8x^5+20x^4) = <span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3+6x²+15x+6-8x^5-20x^4=<span>8x^3+6x²+15x+6
</span>2mx^5+5mx^4+2mx^3=8x^3+6x²+15x+6-6x²-15x-6+ <span>8x^5+20x^4
</span>= 8x^5+20x^4+<span>8x^3= 4(2x^5+5x^4+2x^3)
finally
</span>m(2x^5+5x^4+2x^3)=<span>4(2x^5+5x^4+2x^3), and after simplification
</span>
C: m=4
<span>4. When the expression is factored x²-3x-18 completely,
</span>
one of its factor is x-6
<span>x²-3x-18=0
</span>D= 9-4(-18)= 81, sqrtD=9 x=3-9/2= -6/2= -3, and x=3+9 / 2= 6
so <span>x²-3x-18= (x-6)(x+6)
</span>
<em>Answer:</em>
<em>t = 15</em>
<em>Step-by-step explanation:</em>
<em>t - 12 = 3</em>
<em>t = 3 + 12</em>
<em>t = 15</em>
<h2>
Answer:</h2>
The vertex of the function is:
(-2,-2)
<h2>
Step-by-step explanation:</h2>
We are given a absolute value function f(x) in terms of variable "x" as:
We know that for any absolute function of the general form:
the vertex of the function is : (h,k)
and if a<0 the graph of function opens downwards.
and if a>0 the graph of the function opens upwards.
Hence, here after comparing the equation with general form of the equation we see that:
a= -1<0 , h= -2 and k= -2
Since a is negative , hence, the graph opens down .
Hence, the vertex of the function is:
(-2,-2)
Answer:
just multiply every number by 2 and it should work out.
Step-by-step explanation:
