Answer:
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
Step-by-step explanation:
We have the standard deviation for the sample, which means that the t-distribution is used to solve this question.
The first step to solve this problem is finding how many degrees of freedom, we have. This is the sample size subtracted by 1. So
df = 27 - 1 = 26
99% confidence interval
Now, we have to find a value of T, which is found looking at the t table, with 26 degrees of freedom(y-axis) and a confidence level of 
. So we have T = 2.7787.
The margin of error is:
In which s is the standard deviation of the sample and n is the size of the sample.
The lower end of the interval is the sample mean subtracted by M. So it is 4.9 - 3.7 = 1.2.
The upper end of the interval is the sample mean added to M. So it is 4.9 + 3.7 = 8.6.
The 99% confidence interval for the population mean reduction in anxiety was (1.2, 8.6).
Answer: The answer would be choice C because there is a constant rate of change of 3 :)
Step-by-step explanation:
The answer to the question is that the surface area is 48
S is 27. SRT is 63 becuase of the vertical angles theorem. All angles of a triangle add up to 180, and you already have the other two angles. So its 27
The expected value of health care without insurance is $437.25.
The expected value of health care with insurance is $1,636.40.
<h3>What are the expected values?</h3>
The expected values can be determined by multiplying the respective probabilities by its associated costs.
The expected value of health care without insurance
= (1 x 0) + (0.32 x 1050) + (0.45 x $225)
= $437.25
The expected value of health care with insurance
= (1 x 1580) + (0.32 x 75) + (0.45 x $72)
= $1,636.40
Thus, The expected value of health care without insurance is $437.25.
The expected value of health care with insurance is $1,636.40.
Learn more about Expected value from:
brainly.com/question/13945225
#SPJ1
