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dusya [7]
3 years ago
15

Help Please I'll mark Brainiest!

Chemistry
2 answers:
lyudmila [28]3 years ago
8 0
The shape of the organism is a huge factor, as it could fact for a different creature and/or organism every time. For example, a antelope may have a different form or structure of let’s say a spider, as this is the significant factor of ones shape, the first observation.

Secondly, the colors. As different organism come in different areas of reflections of light, it can easily be identified with this certain color and the way that the light reflects on it. This is another form of visual appearance, and important factor in identification.

Lastly, the pattern. As located on the back, the spikes/thread-looking things sticking out plays a huge factor in finding the organism name and/or identifying it. Every organism has a different pattern, humans being a huge one, all different

Observational studies of organisms is significant to our lives, and it’s greatly helped progress our sciences and society.
madam [21]3 years ago
4 0

Answer:

the unidentified animal  looked like a slug, it looked like it lives or can be in water, the body of the unidentified animal is purple, it seems to have an orange spikes coming out of it's backs.

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Which nucleic acid is responsible for controlling the type of cell that is created? a. pla b. dna crna
avanturin [10]
It would be B. DNA it contains the genetic information for synthesizing specific proteins and other structures that characterize a cell to be a particular cell.
3 0
3 years ago
Fill in the word that correctly completes this sentence.
crimeas [40]
Mixtures are made up of 2 or more substances that are together in the same place but aren’t chemically bonded.
5 0
4 years ago
If 12.5 grams of the original sample of cesium-137 remained after 90.6 years, what was the mass of the original sample?
myrzilka [38]

Answer:

Mass of original sample = 100 g

Explanation:

Half life of cesium-137 = 30.17 years

t_{1/2}=\frac {ln\ 2}{k}

Where, k is rate constant

So,  

k=\frac{\ln2}{t_{1/2}}

k=\frac{\ln2}{30.17}\ year^{-1}

The rate constant, k = 0.02297 year⁻¹

Time = 90.6 years

Using integrated rate law for first order kinetics as:

[A_t]=[A_0]e^{-kt}

Where,  

[A_t] is the concentration at time t

[A_0] is the initial concentration

Initial concentration [A_0] = ?

Final concentration [A_t] = 12.5 grams

Applying in the above equation, we get that:-

12.5\ g=[A_0]e^{-0.02297\times 90.6}

[A_0]=\frac{12.5}{e^{-0.02297\times 90.6}}\ g=100\ g

<u>Mass of original sample = 100 g</u>

8 0
3 years ago
37.9 grams of an unknown substance undergoes a temperature increase of
jenyasd209 [6]

Answer:

1.023 J / g °C

Explanation:

m = 37.9 grams

ΔT = 25.0*C

H = 969 J

c = ?

The equation relating these equation is;

H = mcΔT

making c subject of formulae;

c = H / mΔT

c = 969 J / (37.9 g * 25.0*C)

Upon solving;

c = 1.023 J / g °C

4 0
3 years ago
What is the percent of H in NH3
ale4655 [162]

\frac{h3}{nh3}

\frac{1.008 \times 3}{(14.01) + (1.008 \times 3)}  \times 100\% =
ok, now press calculator. i dont have it now.
6 0
3 years ago
Read 2 more answers
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