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3 years ago

Suppose that we combined 75 g of magnesium with 45 g of nitrogen and heat them up. Predict the product of

Chemistry

1 answer:

juin [17]3 years ago

6 0

Answer:

Mg is the limiting reactant

The theoretical yield is 105.2 g of Mg3N2

Explanation:

3Mg(s) + N2(g) -----> Mg3N2(s)

Number of moles of Mg = 75g/24g/mol = 3.125 moles

3 moles of Mg yields 1 mole of Mg3N2

3.125 moles of Mg yields 3.125 × 1/3 = 1.042 moles of Mg3N2

Number of moles of N2 = 45g/28g/mol = 1.607 moles

1 mole of N2 yields 1 mole of Mg3N2

1.607 moles of N2 yields 1.607 moles Mg3N2

Hence, Mg is the limiting reactant

The theoretical yield of Mg3N2 = 1.042 moles of Mg3N2 × 101 g/mol = 105.2 g of Mg3N2

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A pound of margarine costs $1.39. What is the cost of a kilogram of margarine

den301095 [7]

Answer:

3.064 $

Solution:

First of all we will find the number of pounds contained by one Kg. Therefore, it is found that,

1 Kilogram = 2.20462 Pounds

Hence, as given,

1 Pound of Margarine costs = 1.39 Dollars

So,

2.20462 Pounds Margarine will cost = X Dollars

Solving for X,

X = (2.20462 Pounds × 1.39 Dollars) ÷ 1 Pound

X = 3.064 Dollars

8 0

3 years ago

Select the pair that consists of a base and its conjugate acid in that order. CO32−/CO22−

lana [24]

Answer: The pair that consists of a base and its conjugate acid in that order. $NH_3/NH_4^+$

Explanation:

According to the Bronsted-Lowry conjugate acid-base theory, an acid is defined as a substance which looses donates protons and thus forming conjugate base and a base is defined as a substance which accepts protons and thus forming conjugate acid.

$H_3PO_4\rightarrow H_PO_4{2^-}+2H^+$

$H_2CO_3\rightarrow HCO_3^-+H^+$

$NH_3+H^+\rightarrow NH_4^+$

$HCO_3^-\rightarrow CO_3^{2-}+H^+$

$NH_3$ is gaining a proton, thus it is considered as a brønsted-lowry base and after gaining a proton, it forms $NH_4^+$ which is a conjugate acid.

3 0

3 years ago

A gas that exerts a pressure of

spayn [35]

Answer:

3.089 L

Explanation:

From the given information, provided that the no of moles and the temperature remains constant;

$P_1$ = 15.6 psi

$V_1$ = ???

$P_2$ = 25.43 psi

$V_2$ = 1.895 L

Using Boyle's law:

$P_1V_1 =P_2V_2 \\ \\ V_1 = \dfrac{P_2V_2}{P_1} \\ \\ V_1 = \dfrac{25.43 \times 1.895}{15.6} \\ \\ \mathbf{ V_1 = 3.089 \ L}$

4 0

3 years ago

Rank the compounds in each set in order of increasing acid strength.

Viktor [21]

Answer:

See explanation

Explanation:

For this question, we have to remember the effect of an atom with high electronegativity as "Br". If the "Br" atom is closer to the carboxylic acid group (COOH) we will have an inductive effect. Due to the electronegativity of Br, the electrons of the C-H bond would be to the Br, then this bond would be weaker and the compound will be more acid (because is easier to produce the hydronium ion $H^+$ ).

With this in mind, for A in the last compound, we have 2 Br atoms near to the acid carboxylic group, so, we will have a high inductive effect, then the C-H would be weaker and we will have more acidity. Then we will have the compound with only 1 Br atom and finally, the last compound would be the one without Br atoms.

In B, the difference between the molecules is the position of the "Br" atom in the molecule. If the Br atom is closer to the acid group we will have a higher inductive effect and more acidity.

See figure 1

I hope it helps!

5 0

4 years ago

How much heat will be released when 0.750 moles of carbon monoxide (CO) react in an excess of oxygen gas? 2CO(g) + O2(g) → 2CO2(

lara31 [8.8K]

Answer:

A.566 kJ

B.424 kJ

C.212 kJ

D.755 kJ

Answer: C

Explanation:

3 0

4 years ago

Read 2 more answers