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2 years ago

Suppose that we combined 75 g of magnesium with 45 g of nitrogen and heat them up. Predict the product of

Chemistry

1 answer:

juin [17]2 years ago

6 0

Answer:

Mg is the limiting reactant

The theoretical yield is 105.2 g of Mg3N2

Explanation:

3Mg(s) + N2(g) -----> Mg3N2(s)

Number of moles of Mg = 75g/24g/mol = 3.125 moles

3 moles of Mg yields 1 mole of Mg3N2

3.125 moles of Mg yields 3.125 × 1/3 = 1.042 moles of Mg3N2

Number of moles of N2 = 45g/28g/mol = 1.607 moles

1 mole of N2 yields 1 mole of Mg3N2

1.607 moles of N2 yields 1.607 moles Mg3N2

Hence, Mg is the limiting reactant

The theoretical yield of Mg3N2 = 1.042 moles of Mg3N2 × 101 g/mol = 105.2 g of Mg3N2

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If you are given an ideal gas with pressure (p)259,392.00 pa and temperature (T)=200°c of 1 mole Argon gas in a volume 8.8dm3,ca

GuDViN [60]

Answer: $R=4.82436 \frac{Pa. m^{3}}{mol. K}$

Explanation:

The Ideal Gas equation is:

$P.V=n.R.T$ (1)

Where:

$P$ is the pressure of the gas

$n$ the number of moles of gas

$R=8.3144598 \frac{Pa. m^{3}}{mol. K}$ is the gas constant

$T$ is the absolute temperature of the gas in Kelvin.

$V$ is the volume

It is important to note that the behavior of a real gas is far from that of an ideal gas, taking into account that an ideal gas is a single hypothetical gas. However, under specific conditions of standard temperature and pressure (T=0\°C=273.15 K and P=1 atm=101,3 kPa) one mole of real gas (especially in noble gases such as Argon) will behave like an ideal gas and the constant R will be $8.3144598 \frac{Pa. m^{3}}{mol. K}$ .

However, in this case we are not working with standard temperature and pressure, therefore, even if we are working with Argon, the value of R will be far from the constant of the ideal gases.

Having this clarified, let's isolate $R$ from (1):

$R=\frac{PV}{nT}$ (2)

Where:

$P=259392 Pa$

$n=1 mole$

$T=200\°C=473.15 K$ is the absolute temperature of the gas in Kelvin.

$V=8.8 dm^{3}=0.0088 m^{3}$

$R=\frac{(259392 Pa)(0.0088 m^{3})}{(1 mole)(473.15 K)}$ (3)

Finally:

$R=4.82436 \frac{Pa. m^{3}}{mol. K}$

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Vlada [557]

Answer:

2 valence electrons

Explanation:

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statuscvo [17]

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vladimir1956 [14]

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