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3 years ago

What will happen wen lead react with copper 2 sulfate

1 answer:

4 0

Answer:This is what's known as a metal displacement reaction: the lead substitutes for the copper and ends up precipitating out of solution as insoluble lead (II) sulfate. ... The weight of copper deposited was 15.86gm.

Explanation:

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If 16.29 grams of Na2SO4 is mixed with 3.697 grams of C and allowed to react according to the balanced equation: Na2SO4(aq) + 4

abruzzese [7]

Answer: The limiting reagent in the given chemical reaction is carbon metal.

Explanation:

Excess reagent is defined as the reagent which is present in large amount in a chemical reaction.

Limiting reagent is defined as the reagent which is present in small amount in a chemical reaction. Formation of product depends on the limiting reagent.

To calculate the number of moles, we use the equation:

$\text{Number of moles}=\frac{\text{Given mass}}{\text{Molar mass}}$ .....(1)

For sodium sulfate:

Given mass of sodium sulfate = 16.29 g

Molar mass of sodium sulfate = 142 g/mol

Putting values in equation 1, we get:

$\text{Moles of sodium sulfate}=\frac{16.29g}{142g/mol}=0.115mol$

For carbon:

Given mass of carbon = 3.697 g

Molar mass of carbon = 12 g/mol

Putting values in equation 1, we get:

$\text{Moles of carbon}=\frac{3.697g}{12g/mol}=0.31mol$

For the given chemical reaction:

$Na_2SO_4(aq.)+4C(s)\rightarrow Na_2S(s)+4CO(g)$

By Stoichiometry of the reaction:

4 moles of carbon reacts with 1 mole of sodium sulfate

So, 0.31 moles of carbon will react with = $\frac{1}{4}\times 0.31=0.0775mol$ of sodium sulfate

As, given amount of sodium sulfate is more than the required amount. So, it is considered as an excess reagent.

Thus, carbon metal is considered as a limiting reagent because it limits the formation of product.

Hence, the limiting reagent in the given chemical reaction is carbon metal.

4 0

3 years ago

The characteristic odor of pineapple is due to ethyl butyrate, a compound containing carbon, hydrogen, and oxygen. combustion of

Olin [163]

Answer:

Empirical Formula = C₃H₆O₁

Solution:

Data Given:

Mass of Ethyl Butyrate = 3.61 mg = 0.00361 g

Mass of CO₂ = 8.22 mg = 0.00822 g

Mass of H₂O = 3.35 mg = 0.00335 g

Step 1: Calculate %age of Elements as;

%C = (mass of CO₂ ÷ Mass of sample) × (12 ÷ 44) × 100

%C = (0.00822 ÷ 0.00361) × (12 ÷ 44) × 100

%C = (2.277) × (12 ÷ 44) × 100

%C = 2.277 × 0.2727 × 100

%C = 62.09 %

%H = (mass of H₂O ÷ Mass of sample) × (2.02 ÷ 18.02) × 100

%H = (0.00335 ÷ 0.00361) × (2.02 ÷ 18.02) × 100

%H = (0.9279) × (2.02 ÷ 18.02) × 100

%H = 0.9279 × 0.1120 × 100

%H = 10.39 %

%O = 100% - (%C + %H)

%O = 100% - (62.09% + 10.39%)

%O = 100% - 72.48%

%O = 27.52 %

Step 2: Calculate Moles of each Element;

Moles of C = %C ÷ At.Mass of C

Moles of C = 62.09 ÷ 12.01

Moles of C = 5.169 mol

Moles of H = %H ÷ At.Mass of H

Moles of H = 10.39 ÷ 1.01

Moles of H = 10.287 mol

Moles of O = %O ÷ At.Mass of O

Moles of O = 27.52 ÷ 16.0

Moles of O = 1.720 mol

Step 3: Find out mole ratio and simplify it;

C H O

5.169 10.287 1.720

5.169/1.720 10.287/1.720 1.720/1.720

3.00 5.98 1

3 ≈ 6 1

Result:

Empirical Formula = C₃H₆O₁

8 0

3 years ago

A type of potential energy that is associated with objects that can be stretched or compressed is called ??

Scorpion4ik [409]

The answer is C. Elastic potential energy

4 0

3 years ago

Net ionic equation for Calcium hydroxide reacting with ammonium Chloride?

VMariaS [17]

Answer:

Ca(OH)₂ (aq) + 2NH₄Cl (aq) → CaCl₂ (aq) + 2NH₃ (g) + 2H₂O (l)

Ca²⁺ + 2OH⁻ + 2NH₄⁺ + 2Cl⁻ → Ca⁺² + 2Cl⁻ + 2NH₃ (g) + 2H₂O (l)

2OH⁻ + 2NH₄⁺ → 2NH₃ (g) + 2H₂O (l)

3 0

2 years ago

Read 2 more answers

A kinetics experiment is set up is set up to collect the gas that is generated when a sample of chalk consisting primarily of so

inn [45]

Answer:

Correct option -D

Explanation:

Here, A kinetics experiment is set up is set up to collect the gas that is generated from the cacarbonate and methanoic acid.

Among the given conditions, decreasing the particle size of calcium carbonate only increases the production of gas.

Smaller particles of reactant increases the surface area then followed by rate of reaction will be increases it leads to increases the production of gas.

Therefore, the suitable experimental condition most likely to increase the gas production is-

Decreasing the particle size of the $CaCO_{3}$ by grinding it into a fine powder.

Hence, correct option -D.

4 0

3 years ago

What will happen wen lead react with copper 2 sulfate​

What will happen wen lead react with copper 2 sulfate