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Dovator [93]
2 years ago
7

Choose the largest fraction.

Mathematics
1 answer:
Rufina [12.5K]2 years ago
8 0

Answer:

9/10

Step-by-step explaation:

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Need some help with this please!!
beks73 [17]

Answer:

B,C and B,A

Step-by-step explanation:

Line the cordients and go up right,Then left to find your answer.

4 0
2 years ago
When sending a rectangular package through the U.S. Postal Service, the combined length and girth (perimeter of the cross sectio
weqwewe [10]
Let W = width of package
Let H = height of package
Let L = length of package

The perimeter cab be one of the following:
P = 2(L + W),  or
P = 2(L + H)

The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
 2(L + 10) <= 108
 L + 10 <= 54
 L <= 44 in

When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in

To satisfy both of these conditions requires that L <= 39 in.

Answer: 39 inches
5 0
2 years ago
Solve the system of equations using substitution. y = x + 6 y = –2x – 3 (4, –11) (1, 7) (–3, 3)
sergejj [24]
The answer to the question

5 0
2 years ago
ASAP IM BEING TIME PLEASE!!
andre [41]

x° = 14°, y° = 14°; Use vertical and supplementary angles.

Step-by-step explanation:

The image of the answer is attached below.

In the given image two lines are parallel with transversal.

(9x + 12)° and ∠1 are vertically opposite angles.

Vertically opposite angles are equal.

∠1 = (9x + 12)°

Consecutive interior angles are supplementary.

(9x + 12)° + 3x° = 180°

⇒ 12x° = 168°

⇒ x° = 14°

Sum of the adjacent angles in a line are supplementary.

3x° + (4y – 10)° = 180°

⇒ 3(14)° + 4y° – 10° = 180°

⇒ 4y° = 148°

⇒ y° = 14°

Hence, x° = 14°, y° = 14°; Use vertical and supplementary angles.

6 0
2 years ago
PLEASE ANSWER QUICKLY
Olegator [25]

Answer:

x=3

Step-by-step explanation:

Set equations equal to each other:

x^3-3x^2+2=x^2-6x+11

Subtract two from both sides

x^3-3x^2=x^2-6x+9
Factor out x^2 from the left side

x^2(x-3)=x^2-6x+9

Factor the right side, look for two factors of 9, which add to -6, which is just -3 and-3

x^2(x-3) = (x-3)(x-3)

So as you can see here, we have both sides in factored form, and both have a factor of (x-3) on both sides, and if one of the factors is zero, then the entire thing becomes zero, since 0 * anything= zero.

this means a solution would be at x=3, since it makes the right side 0 * 0 = 0, and the left side (3)^2 * 0 = 0

It's important to notice this, since had we divided by x-3 to make the equation a quadratic, we would've excluded this real solution, because when dividing by x-3 the solution x=3 makes it 0, so we would've been dividing by zero.

So one of the real solutions is at x=3

6 0
1 year ago
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