Answer:
B,C and B,A
Step-by-step explanation:
Line the cordients and go up right,Then left to find your answer.
Let W = width of package
Let H = height of package
Let L = length of package
The perimeter cab be one of the following:
P = 2(L + W), or
P = 2(L + H)
The perimeter of the cross section cannot exceed 108 in.
When the width is 10 in, then
2(L + 10) <= 108
L + 10 <= 54
L <= 44 in
When the height is 15 in, then
2(L + 15) <= 108
L + 15 <= 54
L <= 39 in
To satisfy both of these conditions requires that L <= 39 in.
Answer: 39 inches
x° = 14°, y° = 14°; Use vertical and supplementary angles.
Step-by-step explanation:
The image of the answer is attached below.
In the given image two lines are parallel with transversal.
(9x + 12)° and ∠1 are vertically opposite angles.
Vertically opposite angles are equal.
∠1 = (9x + 12)°
Consecutive interior angles are supplementary.
(9x + 12)° + 3x° = 180°
⇒ 12x° = 168°
⇒ x° = 14°
Sum of the adjacent angles in a line are supplementary.
3x° + (4y – 10)° = 180°
⇒ 3(14)° + 4y° – 10° = 180°
⇒ 4y° = 148°
⇒ y° = 14°
Hence, x° = 14°, y° = 14°; Use vertical and supplementary angles.
Answer:
x=3
Step-by-step explanation:
Set equations equal to each other:

Subtract two from both sides

Factor out x^2 from the left side

Factor the right side, look for two factors of 9, which add to -6, which is just -3 and-3

So as you can see here, we have both sides in factored form, and both have a factor of (x-3) on both sides, and if one of the factors is zero, then the entire thing becomes zero, since 0 * anything= zero.
this means a solution would be at x=3, since it makes the right side 0 * 0 = 0, and the left side (3)^2 * 0 = 0
It's important to notice this, since had we divided by x-3 to make the equation a quadratic, we would've excluded this real solution, because when dividing by x-3 the solution x=3 makes it 0, so we would've been dividing by zero.
So one of the real solutions is at x=3