All categories

2 years ago

Choose the largest fraction.

Mathematics

1 answer:

Rufina [12.5K]2 years ago

8 0

Answer:

9/10

Step-by-step explaation:

You might be interested in

In a triangle ABC, measure of angle B is 90 degrees. AB is 3x-2 units and BC is x+3. If the area of the triangle is 17 sq cm, fo

Scorpion4ik [409]

Answer:

$x=\frac{8}{3}\ cm$

Step-by-step explanation:

we know that

The area of the right triangle ABC is equal to

$A=\frac{1}{2}(AB)(BC)$

we have

$A=17\ cm^2$

$AB=(3x-2)\ cm$

$BC=(x+3)\ cm$

substitute the values

$17=\frac{1}{2}(3x-2)(x+3)$

$34=(3x-2)(x+3)$

$34=3x^2+9x-2x-6$

$3x^2+7x-6-34=0$

$3x^2+7x-40=0$

The formula to solve a quadratic equation of the form

$ax^{2} +bx+c=0$

is equal to

$x=\frac{-b(+/-)\sqrt{b^{2}-4ac}} {2a}$

in this problem we have

$3x^2+7x-40=0$

$a=3\\b=7\\c=-40$

substitute in the formula

$x=\frac{-7(+/-)\sqrt{7^{2}-4(3)(-40)}} {2(3)}$

$x=\frac{-7(+/-)\sqrt{529}} {6}$

$x=\frac{-7(+/-)23} {6}$

$x=\frac{-7(+)23} {6}=\frac{16}{6}=\frac{8}{3}$

$x=\frac{-7(-)23} {6}=-5$

therefore

The solution is

$x=\frac{8}{3}\ cm$

6 0

2 years ago

Josh is building a sandbox for his little sister. He uses these plans, which have a scale of 2 in. : 3 ft.

skelet666 [1.2K]

Answer:

Width of 6ft and length of 9ft

Step-by-step explanation:

The sandbox has a ratio of 2:3. If you plug the numbers in with the ratio, you can find the actual dimensions.

Let x be the length

Let y be the width

(Length)

2in / 3ft = 6in / (x)ft

2in / 3ft = 6in / 9ft

(Width)

2in / 3ft = 4in / (y)ft

2in / 3ft = 4in / 6ft

6 0

2 years ago

DF=78, DE=5x-9, and EF-2x+10, find EF

lbvjy [14]

Answer:

As e is point between df. So we can write df as

df = de + ef

As given df = 78 , de = 5x - 9 , ef = 2x + 10.

So we can write

78 = 5x - 9 + 2x + 10

78 = 7x + 1

On subtracting 1 on booth side

78 - 1 = 7x +1 - 1

77 = 7x

On dividing both side by 7.

11 = x

So x = 11.

So ef = 2x + 10 = 2*11 + 10 = 22 + 10 = 32

Step-by-step explanation:

8 0

2 years ago

Write the equation of the line that passes through the point (6, -2) and is perpendicular to the line

jolli1 [7]

Answer:

y = - 3x + 16

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = $\frac{1}{3}$ x + 8 ← is in slope- intercept form

with slope m = $\frac{1}{3}$

Given a line with slope m then the slope of a line perpendicular to it is

$m_{perpendicular}$ = - $\frac{1}{m}$ = - $\frac{1}{\frac{1}{3} }$ = - 3, so

y = - 3x + c ← is the partial equation of the perpendicular line

To find c substitute (6, - 2) into the partial equation

- 2 = - 18 + c ⇒ c = - 2 + 18 = 16

y = - 3x + 16 ← equation of perpendicular line

6 0

2 years ago

What is the area, in square centimeters, of a right triangle with side

Yanka [14]

Answer:

210 cm^2

Step-by-step explanation:

Let, a=37 cm, b=35 cm, c= 12 cm

s=(a+b+c)/2 = 42 cm

Δ= $\sqrt{s(s-a)(s-b)(s-c)}$

Δ= $\sqrt{42(5)(7)(30)}$

Δ=210 cm^2

5 0

2 years ago