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True [87]
3 years ago
10

Find the interest on $6,000 at 5% for 1 year. I will give brainiest if correct

Mathematics
2 answers:
vagabundo [1.1K]3 years ago
7 0

the answer is 30.Can I get brainliest,im correct.I got it on a quiz

tino4ka555 [31]3 years ago
6 0

Answer:

$300

Step-by-step explanation:

I = prt

I = 6000(.05)(1)

I = 300

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Which is the equation of a line that is perpendicular to 6x – 4y = 9?
natulia [17]

6x – 4y = 9

4y = 6x - 9

y = 6/4 x - 9/4

y = 3/2 x - 9/4 this line has slope = 3/2


perpendicular line, slope is opposite and reciprocal so slope of this line = -2/3


answer:

A. y= - 2/3 x - 4 (only this line has slope = -2/3)

8 0
3 years ago
Karen says the functions f(×)=×+3 and g(×)= -×+7 intersect at x=2 is she correct
frez [133]

Answer:

Yes.

Step-by-step explanation:

To find the point of intersection we solve the system:

y = x + 3

y = -x + 7       Subtract:

0 = 2x - 4

2x = 4

x = 2.

She is correct.

7 0
3 years ago
Read 2 more answers
2 13/18 −z=1 19/36 <br><br>Answer
allsm [11]

Answer:

Answer is z= 43/36

Step-by-step explanation:

We have given,

2 13/18 - z = 1 19/36

Since 2 13/18 = 49/18  and 1 19/36 = 55/36

So we can write,

2 13/18 - z = 1 19/36

or 49/18 - z = 55/36

or 49/18 - 55/36 = z

or (98 -55)/36 = z

or 43/36 = z

Hence we got z = 43/36

3 0
3 years ago
If anyone could help?
Trava [24]

Answer:

y=\frac{5}{7}x and y=\frac{7}{9}x

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In y=\frac{5}{7}x when x=3, y=15/4≈2.14

In y=\frac{3}{5}x when x=3, y=1.8

In y=\frac{7}{9}x when x=3, y≈2.33

In y=\frac{7}{11}x when x=3, y≈1.90

We can observe that in two cases, y=\frac{5}{7}x and y=\frac{7}{9}x, y is greater than 2.


5 0
3 years ago
Two quantities, Pand Q, are connected by
frez [133]

Answer:

P = 0.5Q - 20

Step-by-step explanation:

P = kQ + c

substitute Q = 60 , P = 10 into the equation

10 = 60k + c → (1)

substitute Q = 240, P = 100 into the equation

100 = 240k + c → (2)

subtract (1) from (2) term by term to eliminate c

90 = 180k ( divide both sides by 180 )

\frac{90}{180} = \frac{1}{2} = 0.5 = k

substitute k = 0.5 into (1) and solve for c

10 = 60(0.5) + c

10 = 30 + c ( subtract 30 from both sides )

- 20 = c

then

P = 0.5Q - 20

8 0
2 years ago
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