I believe that the correct given values are:
density = 755 kg/m^3
volume = 640 cm^3
First let us convert volume to m^3 units.
volume = 640 cm^3 * (1 m / 100 cm)^3 = 6.4 x 10^-4 m^3
so the mass is:
mass = 755 kg/m^3 * (6.4 x 10^-4 m^3)
<span>mass = 0.4832 kg = 483.2 g</span>
The car undergoes an acceleration <em>a</em> such that
(45.0 km/h)² - 0² = 2 <em>a</em> (90 m)
90 m = 0.09 km, so
(45.0 km/h)² - 0² = 2 <em>a</em> (0.09 km)
Solve for <em>a</em> :
<em>a</em> = (45.0 km/h)² / (2 (0.09 km)) = 11,250 km/h²
Ignoring friction, the net force acting on the car points in the direction of its movement (it's also pulled down by gravity, but the ground pushes back up). Newton's second law then says that the net force <em>F</em> is equal to the mass <em>m</em> times the acceleration <em>a</em>, so that
<em>F</em> = (4500 kg) (11,250 km/h²)
Recall that Newtons (N) are measured as
1 N = 1 kg • m/s²
so we should convert everything accordingly:
11,250 km/h² = (11,250 km/h²) (1000 m/km) (1/3600 h/s)² ≈ 0.868 m/s²
Then the force is
<em>F</em> = (4500 kg) (0.868 m/s²) = 3906.25 N ≈ 3900 N
Beats only occur when the frequency of two objects is interfere with one another and when those objects are made to identical amplitudes together.
Answer:
The object distance is 92 cm.
Explanation:
let v be the image distance and h be the height of the image, let u the be the object distance and H be the height of the object.
then, the magification of the mirror is given by:
m = -v/u and m = h/H
so, -v/u = h/H
u = -v×H/h
= -(-4.6)×(82)/(4.1)
= 92 cm
Therefore, the object distance is 92 cm.
Answer: 5.76 rads/s
Explanation:
The initial rotation is 55 rpm
1 rev = 2π radians
55 revs = 55 × 2π/1 = 345.58 radians/min
345.58 rads/min = 345.58rads/60s = 5.76 rads/s
