Answer:
Tt = 70 + 135e^-0.031t
13 minutes
Explanation:
Given that :
Initial temperature, Ti = 205°
Temperature after 2.5 minutes = 195°
Temperature of room, Ts= 70
Using the relation :
Tt = Ts + Ce^-kt
Temperature after time, t
When freshly poured, t = 0
205 = 70 + Ce^-0k
205 = 70 + C
C = 205 - 70 = 135°
T after 2.5 minutes to find proportionality constant, k
Tt = Ts + Ce^-kt
195 = 70 + 135e^-2.5k
125 = 135e^-2.5k
125 / 135 = e^-2.5k
0.9259 = e^-2.5k
Take In of both sides :
−0.076989 = - 2.5k
k = −0.076989 / - 2.5
k = 0.031
Equation becomes :
Tt = 70 + 135e^-0.031t
t when Tt = 160
160 = 70 + 135e^-0.031k
90 = 135e^-0.031t
90/135 = e^-0.031t
0.6667 = e^-0.031t
In(0.6667) = - 0.031t
−0.405465 = - 0.031t
t = 0.405465/ 0.031
t = 13.071
t = 13 minutes
Answer:
Frequency = 3.0 Hertz
Explanation:
Given the following data;
Period = 0.333 seconds
To find the frequency;
Mathematically, frequency of a wave is given by the formula;
Frequency = 1/period
Substituting into the formula, we have;
Frequency = 1/0.333
Frequency = 3.0 Hertz
Answer:
2.5 m/s²
Explanation:
Using the formula, v = u + at ( v = Final velocity; u = Initial velocity; t = Time; a = Acceleration)
25 = 0 + 10a
a = 25/10 = 2.5 m/s²
True............................................
<span>D. Pressure increases with increasing depth.
This occurs because there is more weight above you to increase the pressure.
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