Answer:
The work done is 360 J.
Explanation:
Given that,
Mass = 50 kg
Distance =3 m
We need to calculate the work done
The work done is equal to the product of force and displacement.
Using formula of work done


Where, F = force
D = distance
θ = Angle between force and displacement
Put the value into the formula


Hence, The work done is 360 J.
A motion in one dimension is a type of motion that is always along a straight line and has a constant acceleration.
Motion refers to a change in the location (position) of an object or physical body with respect to a reference point, especially due to the action of an external force.
In Science, the motion of an object or physical body is described in terms of the following parameters:
Furthermore, there are three (3) forms of motion based on dimension and these include:
1. Motion in one dimension
2. Motion in two dimension
3. Motion in three dimension
A motion in one dimension (one-dimensional motion) is also referred to as rectilinear or linear motion. Also, it is always along a straight line in any direction and characterized by constant acceleration.
Read more on motion here: brainly.com/question/17675825
Answer: [B]: " (180 <span>- 4y)° " .
_______________________________________________________</span>
Answer:
B
Explanation:
option b stands for less down and cm is less than km
Answer:
For electric field inside cylinder, check image 02 attached
For electric field outside cylinder, check image 03 attached
Explanation:
Let's consider the polarized cylinder as superposition of two cylinders with opposite,equal, uniform charge densities in a way shown in the figure in the "image 01"d attached ;
In general, if we have an object with polarization (P¬) , then we have to take two objects with similar shape to the system, with opposite, equal, and uniform charge densities and then we super-impose these two objects in such a way that the total dipole moment of this superimposed system is equal to the total dipole moment of original system.
Now, we can take the super- imposed system as equivalent to the original system for calculating electric field and potential.
Therefore,
For the electric field inside the cylinder, check the solution in "image 02" i attached
For the electric field outside the cylinder, check, "image 03" i attached.