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Vesna [10]
3 years ago
12

For what value n is 1P3 =nP4?

Mathematics
1 answer:
Serggg [28]3 years ago
3 0

Answer:

I don't know if this helps, just a picture not a link

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Which transformation causes the described change in the graph of the function y = cos x?
kotegsom [21]
Horizontal Shrink: y = cos 2x or if the coefficient of x is greater than 1
Vertical Stretch: y = 2 cos x or if the coefficient if cos x is greater than 1
Horizontal Stretch: y = cos (1/2) x or if the coefficient of x is less than 1
Vertical Shrink: y = (1/2) cos x or the coefficient of cos x is less than 1

The base value is 1 since it is the original coefficient of x and cos x. The values would adjust depending on the original coefficients.

8 0
3 years ago
Can you help me with this question??
Cloud [144]

Answer:

9.42

Step-by-step explanation:

6 0
3 years ago
Read 2 more answers
Which value is a solution to the inequality x – 4 > 15.5?
Alex Ar [27]

Answer:

x>19.5

Step-by-step explanation:

Let's solve your inequality step-by-step.

x−4>15.5

Step 1: Add 4 to both sides.

x−4+4>15.5+4

x>19.5

Answer:

x>19.5

8 0
3 years ago
If AC = x + 5 and AB = 3x - 1... what is the length of BC?
Hatshy [7]
If B is the midpoint of AC, then |AB| = |AC|.
|AB| = 3x + 2
|BC| = 5x - 10
Therefore we have the equation:
3x + 2 = 5x - 10     |subtract 2 from both sides
3x = 5x - 12      |subtract 5x from both sides
-2x = -12      |divide both sides by (-2)
x = 6

Read more on Brainly.com - brainly.com/question/11324096#readmore
4 0
3 years ago
What is the difference? x+5/x+2-x+1/x2+2x
Mrac [35]

Question

x+5/x+2 - x+1/x²+2x

Answer:

= (x² - 4x - 1)/[x (x+2)]

= (x² - 4x - 1)/[x² + 2x]

Step-by-step explanation:

x + 5/x + 2 - x + 1/x² + 2x

We factorise the second denominator to give us :

x + 5/x + 2 - x + 1/x(x + 2)

We find the L.C.M of both denominators which is x(x+2).

[x(x + 5)-(x + 1)] / (x (x + 2))

Expand the bracket

=[x² +5x - x -1] / [x (x + 2)]

=(x² - 4x - 1) / [x (x + 2)]

= (x² - 4x - 1)/ [x (x + 2)]

= (x² - 4x - 1) / [x² + 2x]

6 0
3 years ago
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