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3 years ago

What is the solution of-+-<? 1 1 1 X35

Mathematics

1 answer:

sergij07 [2.7K]3 years ago

3 0

Answer:

A. $-\frac{15}{2} < x< 0$

Step-by-step explanation:

Multiply to remove the fraction, then set equal to 0 and solve.

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X+4y=10<br> -x+5y=8<br> what is the solution set

ziro4ka [17]

$x + 4y = 10 \: \vee \: - x + 5y \\ \Leftrightarrow \: x = 2 \: \vee \: y = 2 \\ \Rightarrow \: (x,y) = (2,2)$

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3 years ago

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Scilla [17]

Answer: The first one

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3 years ago

Twelve jurors are randomly selected from a population of 4 million residents. Of these 4 million residents, it is known that 46

vekshin1

Answer: a) 0.17, b) 0.0363

Step-by-step explanation:

Since we have given that

Number of jurors selected = 12

Number of minorities of jurors = 2

(a) What proportion of the jury described is from a minority race? 

$\dfrac{2}{12}=\dfrac{1}{6}=0.166666\approx0.17$

(b) If 12 jurors are randomly selected from a population where 46% are minorities, what is the probability that 2 or fewer jurors will be minorities?

Let X be the number of jurors who are minorities.

Probability of getting minorities = 0.46

Probability of getting no minorities = 1-0.46 =0.54

$P(X\leq 2)=^{12}C_0(0.54)^{12}+^{12}C_1(0.46)(0.54)^{11}+^{12}C_2(0.46)^2(0.54)^{10}\\\\P(X\leq 2)=0.0363$

(c) What might the lawyer of a defendant from this minority race argue?

Since the number of minorities juror are high among the population.

Hence, a) 0.17, b) 0.0363

7 0

3 years ago

A math test is worth 100 points and has 30 problems. Each problem is worth either 3 points or 4 points. How many 4 point problem

Vinil7 [7]

If you only have 3 point problems you have a total of 3*30=90 points, since the test has 100 points you need 10 extra points, so 10 of those 3 point questions have to be changed to 4 point questions.

So 20 3-point questions and 10 4-point questions.

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3 years ago

M=(N-2)/N solve for N

Tpy6a [65]

M = (N-2)/N

M = N² - 2N

N² - 2N - M = 0

To find N we need to use quadratic formula.

For our equation x = N, a=1, b= -2, c= -M

$x=\frac{-b+/-\sqrt{b^{2}-4ac} }{2a}
\\ \\N=\frac{-(-2)+/-\sqrt{(-2)^{2} -4*1*(-M)} }{2*1}
\\ \\ N=\frac{2+/-\sqrt{4+4M} }{2} \\ \\ N=\frac{-2+/-2\sqrt{1+M} }{2} = -1+/-\sqrt{1+M} \\ \\ N = -1 +\sqrt{1+M} \ or\ N=-1-\sqrt{1+M}$

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3 years ago