(8x^2+5x+3)+(-5x^6-2x^5+4x^2-2x)=
8x^2+5x+3-5x^6-2x^5+4x^2-2x=
-5x^6-2x^5+(8-4)x^2+(5-2)x+3=
-5x^6-2x^5+4x^2+3x+3
Answer: Option B. -5x^6-2x^5+4x^2+3x+3
Answer:
c(12 + 9 + 6)
12(2.25c)
Step-by-step explanation:
12c + 12 (3/4c) + 12 (1/2c)
12(1c) + 12(3/4c) + 12 (1/2c)
12(c + 3/4c + 1/2c)
12(2 1/4c)
12(2.25c)
Or
12c + 12 (3/4c) + 12 (1/2c)
12c + 9c + 6c
c(12 + 9 + 6)
Isolate the VARIABLE by dividing each side by FACTROS that don't contain the VARIABLE .
YOUR answer is <span>x<12
</span>
From one vertex of an octagon you can draw 5 diagonals.
There are 8 vertices in an octagon, and we are choosing one as our starting vertex. There are then 7 vertices left to draw a line to, but 2 of the vertices are already connected to our main vertex (because they are connected along the side of the octagon). That leaves 5 vertices to draw a diagonal to from our original vertex.
