Ask question

Ask question

All categories

3 years ago

11

25% of Mr. Foster's class chose an amber background for their school picture. If 6 students chose an amber background, how many

students are in Mr. Foster's class?

1 answer:

Lelu [443]3 years ago

5 0

Answer:

<h2>24 students</h2>

Step-by-step explanation:

25% of a hundred is one-fourth and because there are six students in a fourth of the whole we are multiplying four and six. 6x 4 is 24.

You might be interested in

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the populatio

Maksim231197 [3]

Answer:

C. 1.8027

Step-by-step explanation:

The exponential population growth model is given by:

$P(t) = P_{0}e^{rt}$

In which P(t) is the population after t years, $P_{0}$ is the initial population and r is the growth rate.

At the beginning of a population study, the population of a large city was 1.65 million people. Three years later, the population was 1.74 million people.

This means that $P_{0} = 1.65, P(3) = 1.74$

Applying this to the equation, we find r. So

$P(t) = P_{0}e^{rt}$

$1.74 = 1.65e^{3r}$

$e^{3r} = \frac{1.74}{1.65}$

$e^{3r} = 1.0545$

Applying ln to both sides

$\ln{e^{3r}} = \ln{1.0545}$

$3r = \ln{1.0545}$

$r = \frac{\ln{1.0545}}{3}$

$r = 0.0177$

So

$P(t) = 1.65e^{0.0177t}$

What would be the population of the city 5 years after the start of the population study?

This is P(5).

$P(t) = 1.65e^{0.0177t}$

$P(5) = 1.65e^{0.0177*5}$

$P(5) = 1.8027$

So the correct answer is:

C. 1.8027

6 0

3 years ago

You are trying to determine if you should accept a shipment of eggs for a local grocery store. About 4% of all cartons which are

padilas [110]

Answer:

0.8809

Step-by-step explanation:

Given that:

The population proportion p = 4% = 4/100 = 0.04

Sample mean x = 16

The sample size n = 300

The sample proportion $\hat p =\dfrac{x}{n}$

= 16/300

= 0.0533

∴

$P(\hat p \leq 0.0533) = P\bigg ( \dfrac{\hat p - p}{\sqrt{\dfrac{P(1-P)}{n}}}\leq\dfrac{0.0533 - 0.04}{\sqrt{\dfrac{0.04(1-0.04)}{300}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.04(0.96)}{300}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{\dfrac{0.0384}{300}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{\sqrt{1.28 \times 10^{-4}}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq\dfrac{0.0133}{0.0113}}\bigg )$

$P(\hat p \leq 0.0533) = P\bigg ( Z\leq1.18}\bigg )$

From the z tables;

= 0.8809

OR

Let X be the random variation that follows a normal distribution;

Then;

population mean $\mu$ = n × p

population mean $\mu$ = 300 × 0.04

population mean $\mu$ = 12

The standard deviation $\sigma = \sqrt{np(1-p)}$

The standard deviation $\sigma = \sqrt{300 \times 0.04(1-0.04)}$

The standard deviation $\sigma = \sqrt{11.52}$

The standard deviation $\sigma = 3.39$

The z -score can be computed as:

$z = \dfrac{x - \mu}{\sigma}$

$z = \dfrac{16 -12}{3.39}$

$z = \dfrac{4}{3.39}$

z = 1.18

The required probability is:

P(X ≤ 10) = Pr (z ≤ 1.18)

= 0.8809

5 0

3 years ago

A bird's path is modeled by the following graph. Use the graph below to answer

VARVARA [1.3K]

Answer:

The greatest height the bird reached was 26 feet

At 5 seconds the bird was going down.

Step-by-step explanation:

3 0

3 years ago

What is 5? A prime Or composite?

TEA [102]

IT is prime. Nothing other than itself and 1 can go into it.

8 0

3 years ago

Read 2 more answers

X^2-8x+15=0<br> SOLVE by showing work and using the AC method then find the solutions

Alexeev081 [22]

Ac method
for y=ax^2+bx+c
the ac method is normally used for when a≠1
it is used as an aid to help factor

so

0=1x^2-8x+15
multiply a and c (1 times 15=15)
what 2 numbers mulitply to get 15 and add to get -8?
-3 and -5
split the middle up to that
0=1x^2-3x-5x+15
group
0=(x^2-3x)+(-5x+15)
undistribute
0=x(x-3)-5(x-3)
undistribute (x-3)
0=(x-5)(x-3)
set to zero
x-5=0
x=5

x-3=0
x=3

solutions are x= 3 and 5

6 0

4 years ago