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IRINA_888 [86]
3 years ago
15

(x + 3)/(3x - 2) - (x - 3)/(3x + 2) = - 22/(9x ^ 2 - 4)

Mathematics
1 answer:
ICE Princess25 [194]3 years ago
7 0

Answer:

x = -1

Step-by-step explanation:

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Solve the perimeter formula of a rectangle for w and use the resulting formula to find the width of a rectangle with a length of
dusya [7]

Answer:

Step-by-step explanation:w=1cm

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11. ¿Es mayor 1/4 que 0.50? Justifica tu pregunta​
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Eh yo creo que no, si estoy mal los siento

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2 years ago
In Class 1, what is the median score? A) 70 B) 70.5 C) 71.5 D) 72
evablogger [386]

Answer:

B)  70.5

Step-by-step explanation:

Median = middle value when the values are placed in order.

If there are two middle values, the median is the mean of those two values.

<u>Class 1</u>

45 46 51 52 53 53 61 63 64 65 66 68 70 <u>70 71</u> 73 76 77 79 81 82 83 84 87 90 92 93 95

There are 28 values in Class 1.

Therefore, there are two middle values: 14th and 15th values

14th value = 70

15th value = 71

\implies \textsf{Median}=\dfrac{70+71}{2}=70.5

3 0
2 years ago
Read 2 more answers
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They each got 1/8 of a slice
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2 years ago
A local police chief claims that 31% of all drug-related arrests are never prosecuted. A sample of 500 arrests shows that 27% of
Elis [28]

Answer:

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

Step-by-step explanation:

1) Data given and notation

n=500 represent the random sample taken

X represent the number of arrests that were not prosecuted.

\hat p=0.27 estimated proportion of arrests that were not prosecuted

p_o=0.31 is the value that we want to test

\alpha=0.02 represent the significance level

Confidence=98% or 0.98

z would represent the statistic (variable of interest)

p_v represent the p value (variable of interest)  

2) Concepts and formulas to use  

We need to conduct a hypothesis in order to test the claim that the true proportion is less than 0.31.:  

Null hypothesis:p\geq 0.31  

Alternative hypothesis:p < 0.31  

When we conduct a proportion test we need to use the z statisitc, and the is given by:  

z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}} (1)  

The One-Sample Proportion Test is used to assess whether a population proportion \hat p is significantly different from a hypothesized value p_o.

3) Calculate the statistic  

Since we have all the info requires we can replace in formula (1) like this:  

z=\frac{0.27 -0.31}{\sqrt{\frac{0.31(1-0.31)}{500}}}=-1.933  

4) Statistical decision  

It's important to refresh the p value method or p value approach . "This method is about determining "likely" or "unlikely" by determining the probability assuming the null hypothesis were true of observing a more extreme test statistic in the direction of the alternative hypothesis than the one observed". Or in other words is just a method to have an statistical decision to fail to reject or reject the null hypothesis.  

The significance level provided \alpha=0.02. The next step would be calculate the p value for this test.  

Since is a left tailed test the p value would be:  

p_v =P(Z  

If we compare the p value obtained and the significance level given \alpha=0.02 we have p_v>\alpha so we can conclude that we have enough evidence to FAIL reject the null hypothesis, and we can said that at 2% of significance the proportion of arrests that were not prosecuted is not significanlty less than 0.31.  

3 0
3 years ago
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