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2 years ago

write an equation in point slope form of the line that passes through the point (-8,-2) and had a slope of m=5

Mathematics

1 answer:

Ede4ka [16]2 years ago

3 0

Answer:

5x - y + 38 = 0

Step-by-step explanation:

solution:

slope(m) = 5

(x1 , y1) = (-8 , -2)

we know that,

(y - y1) = m(x -x1)

or, (y - -2) = 5(x - -8)

or, y+2 = 5(x + 8)

or, y+2 = 5x +40

or, 5x - y + 38 = 0 is the required equation

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Sarah has 2 3/4 more meters of rope.

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3 years ago

the sum of the first nine terms of an arithmetic series is 162, and the sum of the first 12 terms is 288. Determine the first fi

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Answer:

$\boxed{\pink{\tt \leadsto Sum \ of \ first \ five \ terms \ is \ 50 . }}$

Step-by-step explanation:

Given that , the sum of the first nine terms of an arithmetic series is 162 and the sum of the first 12 terms is 288.

$\boxed{\red{\bf \bigg\lgroup For \ answer \ refer \ to \ attachment \bigg\rgroup }}$

<h3>Related Information :- </h3>

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2 years ago

Solve for x: 3-(2x-5)<-4(x+2)

trapecia [35]

3-(2x-5)=-4(x+2)

We simplify the equation to the form, which is simple to understand
3-(2x-5)=-4(x+2)

Remove unnecessary parentheses
3-2x+5=-4*(x+2)

Reorder the terms in parentheses
3-2x+5=+(-4x-8)

Remove unnecessary parentheses
+3-2x+5=-4x-8

We move all terms containing x to the left and all other terms to the right.
-2x+4x=-8-3-5

We simplify left and right side of the equation.
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3 years ago

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What is the multiplicative inverse of 5 in z11, z12, and z13? you can do a trial-and-error search using a calculator or a pc?

grin007 [14]

A multiplicative inverse of an integer a is an integer x such that the product ax is congruent to 1 with respect to the modulus m.

1. $Z_{11}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{4};$
$5\cdot 4=20=\overline{9};$
$5\cdot 5=25=\overline{3};$
$5\cdot 6=30=\overline{8};$
$5\cdot 7=35=\overline{2};$
$5\cdot 8=40=\overline{7};$
$5\cdot 9=45=\overline{1};$
$5\cdot 10=50=\overline{6}.$

The multiplicative inverse of 5 in $Z_{11}$ is 9.

2. $Z_{12}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{3};$
$5\cdot 4=20=\overline{8};$
$5\cdot 5=25=\overline{1};$
$5\cdot 6=30=\overline{6};$
$5\cdot 7=35=\overline{11};$
$5\cdot 8=40=\overline{4};$
$5\cdot 9=45=\overline{9};$
$5\cdot 10=50=\overline{2};$
$5\cdot 11=55=\overline{7}.$

The multiplicative inverse of 5 in $Z_{12}$ is 5.

3. $Z_{13}=\{\overline{0},\overline{1},\overline{2},\overline{3},\overline{4},\overline{5},\overline{6},\overline{7},\overline{8},\overline{9},\overline{10},\overline{11},\overline{12}\}.$

Check:

$5\cdot 0=\overline{0};$
$5\cdot 1=\overline{5};$
$5\cdot 2=\overline{10};$
$5\cdot 3=15=\overline{2};$
$5\cdot 4=20=\overline{7};$
$5\cdot 5=25=\overline{12};$
$5\cdot 6=30=\overline{4};$
$5\cdot 7=35=\overline{9};$
$5\cdot 8=40=\overline{1};$
$5\cdot 9=45=\overline{6};$
$5\cdot 10=50=\overline{11};$
$5\cdot 11=55=\overline{3};$
$5\cdot 12=60=\overline{8}.$

The multiplicative inverse of 5 in $Z_{13}$ is 8.

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2 years ago

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