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AleksandrR [38]
3 years ago
13

ANSWER ASAPPPP FORR BRAINLIEST

Mathematics
1 answer:
miv72 [106K]3 years ago
4 0

Answer: the first one

Step-by-step explanation:

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I NEED HELP!!!<br> 0+0<br> PLEASE HELP!!<br> 50 pts
Burka [1]

Answer:

I think the answer is 0

Step-by-step explanation:

7 0
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Which triangle congruence postulate can be used to prove that FEH=HGF?
Natali5045456 [20]

Answer:

Option (2).

Step-by-step explanation:

From the figure attached,

EFGH is a quadrilateral and FH is line which divides the quadrilateral into two right triangles, ΔFEH and ΔHGF.

In ΔFEH and ΔHGF,

Sides EH ≅ FG [Given]

FH ≅ FH [reflexive property]

ΔFEH ≅ ΔHGF [HL (Hypotenuse - length) postulate of congruence]

Option (2) will be the answer.

7 0
3 years ago
The present year is 2014. Which year comes AFTER THE NEXT 3 years?
FinnZ [79.3K]
The answer to this question is 2017
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3 years ago
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Evaluate : limx→ tan2-sin2x x3
GrogVix [38]

Given:

\lim _{x\to0}\frac{\tan 2x-\sin 2x}{x^3}

Solve:

\lim _{x\to0}\frac{\tan 2x-\sin 2x}{x^3}

Use l'hopital's rule:

\begin{gathered} =\lim _{x\to0}\frac{\frac{d}{dx}(-\sin 2x+\tan 2x)}{\frac{d}{dx}(x^3)} \\ =\lim _{x\to0}\frac{-2\cos (2x)+2\tan ^2(2x)+2}{3x^2} \end{gathered}

Simplify:

\begin{gathered} =\lim _{x\to0}\frac{-2\cos (2x)+2\tan ^2(2x)+2}{3x^2} \\ =\lim _{x\to0}\frac{2(-\cos (2x)+\tan ^2(2x)+1)}{3x^2} \end{gathered}

Apply the constant multiple rule:

\begin{gathered} \lim _{x\to0}cf(x)=c\lim _{x\to0}f(x) \\ \text{With c=}\frac{2}{3} \\ f(x)=\frac{-\cos (2x)+\tan ^2(2x)+1}{x^2} \end{gathered}\begin{gathered} =\frac{2\lim _{x\to0}\frac{-\cos (2x)+\tan ^2(2x)+1}{x^2}}{3} \\ =\frac{2\lim _{x\rightarrow0}\frac{(4\tan ^2(2x)+4)\tan (2x)+2\sin (2x)}{2x}}{3} \end{gathered}

Similary :

\begin{gathered} =\frac{2\lim _{x\to0}(2\cos (2x)+12\tan ^4(2x)+16\tan ^2(2x)+4)}{3} \\ =\frac{2(6)}{3} \\ =4 \end{gathered}

8 0
2 years ago
Y=3x-2 solve for x plz help 40 points!!!
Svetlanka [38]

Answer:

x=\frac{y+2}{3}

Step-by-step explanation:

1) since we are solving for x we want x to be the ONLY thing on the other side of the equation symbol:

for ex. x=

2) to do this, we need to eliminate -2, we eliminate -2 by adding 2 on both sides:

y+2=3x-2+2

y+2=3x

remove 3 by dividing it on both sides(opposite operation)

\frac{y+2}{3}=x

this is our final equation since we have solved for x

hope this helps

6 0
3 years ago
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