a parking meter accepts only 20p coins or 50p coins.On one day, 39 coins were collected with a total value of $11.40. find how m
any 50p coins were collected.
2 answers:
Answer:
x + Y = 39 or x = 39-y
20x + 50y = 1.40
20 (39 - y) + 50y = 11.40
7.80 - 20y + 50y = 11.40
30y = 11.40 - 7.80
30y = 3.60
y = 3.60/30
y = 12 50p coins were collected.
x = 39 - 12 = 27 20p coins were collected.
Proof:
20*27 + 50*12 = 11.40
5.40 + 6 = 11.40
11.40 = 11.40
I hope it helps.
Answer:
12 50p coins were collected
Step-by-step explanation:
Let x represent the number of 50p coins. Then 39-x is the number of 20p coins. The total value of coins collected was ...
20(39-x) +50(x) = 1140
780 +30x = 1140 . . . . . . . simplify
30x = 360 . . . . . . . . subtract 780
x = 12 . . . . . . . . . divide by 30
12 of the 50p coins were collected.
__
39 -12 = 27 of the 20p coins were collected.
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