Answer:
Airplane speed relative to the ground is 260 km/h and θ = 22.6º direction from north to east
Explanation:
This is a problem of vector composition, a very practical method is to decompose the vectors with respect to an xy reference system, perform the sum of each component and then with the Pythagorean theorem and trigonometry find the result.
Let's take the north direction with the Y axis and the east direction as the X axis
Vy = 240 km / h airplane
Vx = 100 Km / h wind
a) See the annex
Analytical calculation of the magnitude of the speed and direction of the aircraft
V² = Vx² + Vy²
V = √ (240² + 100²)
V = 260 km/h
Airplane speed relative to the ground is 260 km/h
Tan θ = Vy / Vx
tan θ = 100/240
θ = 22.6º
Direction from north to eastb
b) What direction should the pilot have so that the resulting northbound
Vo = 240 km/h airplane
Vox = Vo cos θ
Voy = Vo sin θ
Vx = 100 km / h wind
To travel north the speeds the x axis (East) must add zero
Vx -Vox = 0
Vx = Vox = Vo cos θ
100 = 240 cos θ
θ = cos⁻¹ (100/240)
θ = 65.7º
North to West Direction
The speed in that case would be
V² = Vx² + Vy²
To go north we must find Vy
Vy² = V² - Vx²
Vy = √( 240² - 100²)
Vy = 218.2 km / h
Answer:
force acting on the parent = 25 N .
Explanation:
According to third law of Newton , there is equal and opposite reaction to every action . Here force by the parent on child is action and the force by child on parent is reaction . The former is given as 25 N so force by child on parent will also be 25 N .
Answer is 25 N .
Heaver objects because they have greater mass
Conservation of energy explains that energy can only be transferred between different forms of energy
This question is stated in a complicated way, but all the information we need is right there waiting to be untangled.
We'll start the clock when Todd arrives. At that time:
-- Kate has 5 done. Todd has none yet. Todd is 5 units behind.
From then on:
-- The clock is running. Kate adds 4 an hour to her total. Todd adds 5 an hour.
-- She started out 5 ahead of Todd when he arrived, but Todd does 1 more than Kate every hour.
-- So Kate's 'lead' shrinks by 1 every hour.
-- So <em>Todd will catch up with Kate</em> <em>in 5 hours</em>.
That's the answer to the question ... How long ? It doesn't ask us how many stockings have been filled, but that's easy for us to figure out:
-- Kate had 5 done when the clock started. She fills 4 every hour. After 5 hours, she has (5 x 4) = 20 more filled, and a total of 25 ready to sell.
-- Todd started out with none done. He fills 5 every hour. After 5 hours, he has (5 x 5) = 25 filled and ready to sell. He has caught up with Kate in 5 hours.
