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valkas [14]
2 years ago
6

A scientist is measuring various properties of a sound wave. She measures the value 340 m/s. Which of the following wave charact

eristics could this value correspond to?
A.
wavelength of the sound wave
B.
period of the sound wave
C.
wave speed of the sound wave
D.
frequency of the sound wave
Physics
2 answers:
n200080 [17]2 years ago
8 0
It’s either. A or D
cluponka [151]2 years ago
8 0

Answer:

B. period of the sound wave

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gavmur [86]
A solar eclipse occurs when the moon crosses in front of the Sun, blocking some or all of its rays. A lunar eclipse happens when the moon is directly behind the earth, blocking the moon from receiving light. The only light comes from the light on earth's reflected shadow.

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Some doctors and eye care specialists say that after someone complains of blindness after looking at a solar eclipse unaided, they can see what the Sun and moon looked like at the time that they looked at it, as it is burned onto their retinas. 
8 0
3 years ago
The image shows a roller coaster.
mariarad [96]
I believe the answer is c but I’m not 100% sure
8 0
3 years ago
A rope exerts a 280 N force while pulling an 80 Kg skier upward along a hill inclined at 12o. The rope pulls parallel to the hil
user100 [1]

Answer:

The speed of the skier after moving 100 m up the slope are of V= 25.23 m/s.

Explanation:

F= 280 N

m= 80 kg

α= 12º

μ= 0.15

d= 100m

g= 9,8 m/s²

N= m*g*sin(α)

N= 163 Newtons

Fr= μ * N

Fr= 24.45 Newtons

∑F= m*a

a= (280N - 24.5N) / 80kg

a= 3.19 m/s²

d= a * t² / 2

t=√(2*d/a)

t= 7.91 sec

V= a* t

V= 3.19 m/s² * 7.91 s

V= 25.23 m/s

4 0
3 years ago
Which best describes two counteracting forces on an object
Natali5045456 [20]

The correct answer is B two children pulling apart a wishbone

Let me know if you have any questions, and have a nice day!

6 0
3 years ago
Read 2 more answers
2. An alternating current is represented by the equation I=20sin 100mt.
Sladkaya [172]

Explanation:

The general equation of an AC current is given by :

I=I_o sin\omega t

Where

I₀ is the peak value of current

\omega is angular frequency

As\ \omega=2\pi f

So,

f=\dfrac{\omega}{2\pi}\\\\f=\dfrac{100\pi}{2\pi}\\\\f=50\ Hz

We know that,

I_{rms}=\dfrac{I_0}{\sqrt{2}}\\\\=\dfrac{20}{\sqrt{2}}\\\\I_{rms}=14.14\ A

So, the frequency is 50 Hz and the maximum rms value of current is 14.14 A.

3 0
2 years ago
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