The statements from both Technicians A and B are correct.
Answer: Option C
<u>Explanation:</u>
A typical MAP sensors comprises with a ceramic or silicon wafers, sealed with an ideal vacuum on one side and a suction manifold on the other. When the engine (motor) vacuum varies, the differential pressure across the board changes the output voltage or frequency to the MAP sensor. So, sensor vacuum to be increased if injection pulse widths increase.
Most pressure sensors operate at 5 volts from a computer and return a signal (voltage or frequency) based on the pressure applied to the sensor (vacuum). When testing the MAP sensor, make sure that the vacuum hose and hose connections are tightly connected to the engine vacuum source. According to this, concluding that the statements from both technicians are correct.
Answer:
<h3>0.42s</h3>
Explanation:
Velocity = Displacement/time
Displacement of the horse is the distance covered in a specified direction
Total distance of the horse towards the right = 15m + 20m = 35m
Total distance of the horse towards the left = 4m
Displacement = Distance towards the right - Distance towards the left
Displacement = 35m-4m
Displacement = 31m
Time taken = 74seconds
substitute the values gotten into the velocity formula
average velocity = 31m/74s
average velocity = 0.42m/s
Hence the magnitude of its average velocity is 0.42s
The period of the pendulum depends only on the length from the pivot to the "center of mass". So if the string has no mass, then the amount of mass on the end doesn't make any difference.
But if the pendulum is suspended on, say, a chain with mass, then the more mass on the bottom, the lower the center of mass is, and the longer the period is.
Answer: C = Q/4πR
Explanation:
Volume(V) of a sphere = 4πr^3
Charge within a small volume 'dV' is given by:
dq = ρ(r)dV
ρ(r) = C/r^2
Volume(V) of a sphere = 4/3(πr^3)
dV/dr = (4/3)×3πr^2
dV = 4πr^2dr
Therefore,
dq = ρ(r)dV ; dq =ρ(r)4πr^2dr
dq = C/r^2[4πr^2dr]
dq = 4Cπdr
FOR TOTAL CHANGE 'Q', we integrate dq
∫dq = ∫4Cπdr at r = R and r = 0
∫4Cπdr = 4Cπr
Q = 4Cπ(R - 0)
Q = 4CπR - 0
Q = 4CπR
C = Q/4πR
The value of C in terms of Q and R is [Q/4πR]
Answer:
Angular momentum is conserved if there are no external forces
P1 = P2
I1 ω1 = I2 ω2
ω2 / ω1 = I1 / I2
If the skater pulls their arms in (I2 < I1) then the angular speed must increase for angular momentum to be conserved.
