Need help on this thank you

Izzy had an 82 and an 88 on his first two tests and believed that he did well enough on his final exam to keep his B average. H

Anastaziya [24]

Answer:

73

Step-by-step explanation:

to find the mean you need to add up all grades and divide if by the number of terms you added

(82 + 88 + x) ÷ 3 = 69 (since we don't know the third grade let's call it x)

170 + x = 69 × 3

x = 37

if the digits transposed the the actual grade would be 73

5 0

3 years ago

The corners of a meadow are shown on a coordinate grid. Ethan wants to fence the meadow. What length of fencing is required?

Nuetrik [128]

Answer:

34.6 units

Step-by-step explanation:

The lenght of fencing required is the total distance between point A to B, B to C, C to D, and D to A. That is the distance between all 4 corners of the meadow.

The coordinates of the corners of the meadow is shown on a coordinate plane in the attachment. (See attachment below).

Let's use the distance formula to calculate the distance between the 4 corners of the meadow using their coordinates as follows:

Distance between point A(-6, 2) and point B(2, 6):

$AB = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$A(-6, 2)) = (x_1, y_1)$

$B(2, 6) = (x_2, y_2)$

$AB = \sqrt{(2 - (-6))^2 + (6 - 2)^2}$

$AB = \sqrt{(8)^2 + (4)^2}$

$AB = \sqrt{64 + 16} = \sqrt{80}$

$AB = 8.9$ (nearest tenth)

Distance between B(2, 6) and C(7, 1):

$BC = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$B(2, 6) = (x_1, y_1)$

$C(7, 1) = (x_2, y_2)$

$BC = \sqrt{(7 - 2)^2 + (1 - 6)^2}$

$BC = \sqrt{(5)^2 + (-5)^2}$

$BC = \sqrt{25 + 25} = \sqrt{50}$

$BC = 7.1$ (nearest tenth)

Distance between C(7, 1) and D(3, -5):

$CD = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$C(7, 1) = (x_1, y_1)$

$D(3, -5) = (x_2, y_2)$

$CD = \sqrt{(3 - 7)^2 + (-5 - 1)^2}$

$CD = \sqrt{(-4)^2 + (-6)^2}$

$CD = \sqrt{16 + 36} = \sqrt{52}$

$CD = 7.2$ (nearest tenth)

Distance between D(3, -5) and A(-6, 2):

$DA = \sqrt{(x_2 - x_1)^2 + (y_2 - y_1)^2}$

Let,

$D(3, -5) = (x_1, y_1)$

$A(-6, 2) = (x_2, y_2)$

$DA = \sqrt{(-6 - 3)^2 + (2 - (-5))^2}$

$DA = \sqrt{(-9)^2 + (7)^2}$

$DA = \sqrt{81 + 49} = \sqrt{130}$

$DA = 11.4$ (nearest tenth)

Length of fencing required = 8.9 + 7.1 + 7.2 + 11.4 = 34.6 units

8 0

3 years ago

What is the opposite of (-6v + 1)?

jarptica [38.1K]

I think it will be (6v-1) because its the opposite.

8 0

3 years ago

Find the 7th term of the geometric sequence –4, 12, –36, 108, –324,...

maks197457 [2]

Answer:

a

Step-by-step explanation:

a=-4 r=12/-4=-3

T7= ar^n-1

= (-4)(-3)^7-1

=-2916

5 0

3 years ago

The frequency of vibrations of a vibrating violin string isgiven by

arlik [135]

Answer:a. [tex] $f\propto L$ [\tex]

b. [tex] f \propto \sqrt{T} [\tex]

c. [tex] f \propto \frac{1}{\sqrt{P}} [\tex]

I. Decrease in length increases leads to increase in pitch.

II. Increase in tension leads to increase in pitch.

III. Increase in linear density reduces the pitch

Step-by-step explanation: I. Since the frequency is inversely proportional to the length increase in length leads to decrease in frequency likewise decrease in length leads to increase in frequency.

II. Since the frequency is directly proportional to the square root of the tension increase in tension leads to increase in frequency likewise decrease in tension leads to decrease in frequency.

III.since the frequency is inversely proportional to the square root of the linear density so increase in linear density leads to decrease in frequency and likewise decrease in linear density leads to increase in frequency.

7 0

3 years ago