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Alina [70]
3 years ago
12

A "shielding gas" mixture of argon and carbon dioxide is sometimes used in welding to improve the strength of the weld. if a gas

cylinder of this two-part mixture was at 4.0 atm pressure and this mixture was 90.% argon, what would be the pressure due to the carbon dioxide gas component?
Chemistry
2 answers:
kodGreya [7K]3 years ago
6 0
Dalton's Law of Partial Pressures, commonly applied to ideal gases, explains that the partial pressures of individual, non-reacting gases are equal to the total pressure exerted by the gas mixture. The given gas mixture composed of 90% argon and 10% carbon dioxide has the following partial pressures: 3.6 atm for argon and 0.4 atm for carbon dioxide (answer).
Radda [10]3 years ago
3 0

Answer is: the pressure due of carbon dioxide gas is 0.4 atm.

p(mixture) = 4.0 atm; mixture of argon and carbon dioxide gas.

ω(Ar) = 90% ÷ 100%.

ω(Ar) = 0.9; percentage of argon gas in mixture.

p(Ar) = 0.9 · 4.0 atm.

p(Ar) = 3.6 atm; pressure of argon gas.

The total pressure of an ideal gas mixture is the sum of the partial pressures of the gases in the mixture.

p(mixture) = p(Ar) + p(CO₂).

p(CO₂) = 4 atm - 3.6 atm.

p(CO₂) = 0.4 atm; pressure of carbon dioxide gas.

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Iron is a :<br><br>A. substance<br>B. heterogenous mixture<br>C. homogenous mixture​
wlad13 [49]

Answer:

a: iron is a substance

Explanation:

because its hard and brittle and classified as a metal

4 0
3 years ago
A 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, what is the volume? *
elena-14-01-66 [18.8K]

The new volume when pressure increases to 2,030 kPa is 0.8L

BOYLE'S LAW:

The new volume of a gas can be calculated using Boyle's law equation:

P1V1 = P2V2

Where;

  1. P1 = initial pressure (kPa)
  2. P2 = final pressure (kPa)
  3. V1 = initial volume (L)
  4. V2 = final volume (L)

According to this question, a 4.0 L balloon has a pressure of 406 kPa. When the pressure increases to 2,030 kPa, the volume is calculated as:

406 × 4 = 2030 × V2

1624 = 2030V2

V2 = 1624 ÷ 2030

V2 = 0.8L

Therefore, the new volume when pressure increases to 2,030 kPa is 0.8L.

Learn more about Boyle's law calculations at: brainly.com/question/1437490?referrer=searchResults

3 0
3 years ago
0.475 g H, 7.557 gS, 15.107 g O. Express your answer as a chemical formula.
max2010maxim [7]

Answer:

H₂SO₄

Explanation:

We have a compound formed by 0.475 g H, 7.557 g S, 15.107 g O. In order to determine the empirical formula, we have to follow a series of steps.

Step 1: Calculate the total mass of the compound

Total mass = mass H + mass S + mass O = 0.475 g + 7.557 g + 15.107 g

Total mass = 23.139 g

Step 2: Determine the percent composition.

H: (0.475g/23.139g) × 100% = 2.05%

S: (7.557g/23.139g) × 100% = 32.66%

O: (15.107g/23.139g) × 100% = 65.29%

Step 3: Divide each percentage by the atomic mass of the element

H: 2.05/1.01 = 2.03

S: 32.66/32.07 = 1.018

O: 65.29/16.00 = 4.081

Step 4: Divide all the numbers by the smallest one

H: 2.03/1.018 ≈ 2

S: 1.018/1.018 = 1

O: 4.081/1.018 ≈ 4

The empirical formula of the compound is H₂SO₄.

7 0
3 years ago
Enter the chemical formula of a binary molecular compound of hydrogen and a Group 6A element that can reasonably be expected to
Ber [7]

Answer:

H₂Se

Explanation:

A way of estimating the acidity of a weak acid is by analizing the<em> stability of the formed anion</em>. In this case, we should find a Group 6A element that in its anionic forms (HX⁻ and X⁻²) is more stable than HS⁻ and S⁻², thus it would be more acidic in aqueous solution.

The anionic forms of Se are more stable than the forms of S, similarly to how Br⁻ is more stable than Cl⁻.

8 0
3 years ago
1. Ethene, C2H4, burns in oxygen according to the equation. In an experiment, 10cm3 of ethene was burnt in 50cm3 of oxygen.
lukranit [14]

Answer:

3333333333333337ysh

6 0
3 years ago
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