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gulaghasi [49]
3 years ago
6

Reaction of hexamethylbenzene with methyl chloride and aluminum chloride gave a salt a, which, on being treated with aqueous sod

ium bicarbonate solution, yielded compound
b. suggest a mechanism for the conversion of hexamethylbenzene to b by correctly inferring the structure of a
Chemistry
1 answer:
GREYUIT [131]3 years ago
7 0

Answer: -

The first step involves reaction of methyl chloride with AlCl₃.

Then the compound A generates by attack of pi bond on CH₃.

Then there is a rearrangement of the carbocation from 2° to 3°.

Finally a H⁺ is lost to give B

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If the concentration of Mg2+ in the solution were 0.039 M, what minimum [OH−] triggers precipitation of the Mg2+ ion? (Ksp=2.06×
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Answer:

2.30 × 10⁻⁶ M

Explanation:

Step 1: Given data

Concentration of Mg²⁺ ([Mg²⁺]): 0.039 M

Solubility product constant of Mg(OH)₂ (Ksp): 2.06 × 10⁻¹³

Step 2: Write the reaction for the solution of Mg(OH)₂

Mg(OH)₂(s) ⇄ Mg²⁺(aq) + 2 OH⁻(aq)

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We will use the following expression.

Ksp = 2.06 × 10⁻¹³ = [Mg²⁺] × [OH⁻]²

[OH⁻] = 2.30 × 10⁻⁶ M

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