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Lelechka [254]
3 years ago
5

Most reactions, including enzyme-catalyzed reactions, proceed faster at higher temperatures. However, for a given enzyme, the ra

te drops off abruptly at a certain temperature. Account for this behavior.
Chemistry
1 answer:
Tju [1.3M]3 years ago
7 0

Answer:

It has denatured

Explanation:

When the temperature get high the enzymes tend to change shape and denaturing occurs.

You might be interested in
Xco3 enter the group number of x
Mademuasel [1]

We know that C has a formal charge of +4 while each O element has a formal charge of -2, therefore the formal charge of X is:

X + 2 – 2 * 3 = 0

X + 2 – 6 = 0

X = 4

<span>So X has a group number of 4.</span>

4 0
3 years ago
Ferrous sulfate (FeSO4) was used in the
BARSIC [14]

Ferrous sulfate (FeSO4) is obtained by the reaction of aqueous ferric sulfate with gaseous sulfur dioxide and water according to the equation below:

Aqueous ferric sulfate = Fe_2(SO_4)_3_{(aq)}

Gaseous sulfur dioxide = SO_2_{(g)}

Water = H_2O_{(l)}

Aqueous sulfuric acid =  H_2SO_4_{ (aq)}

Aqueous ferrous sulfate =  FeSO_4_{ (aq)}

Thus, the balance equation becomes:

Fe_2(SO_4)_3_{(aq)} +  SO_2_{(g)} + 2H_2O_{(l)} ---> 2 H_2SO_4_{ (aq)} + 2 FeSO_4_{ (aq)}

More on ferrous sulfate can be found here:  brainly.com/question/10834028

6 0
3 years ago
You are conducting a plant growth experiment and need to generate a solution with growth factor, auxin or indole-3-acetic acid.
Yuki888 [10]

Answer:

7,01 g of indole-3-acetic acid

Explanation:

The milimolar concentration (mM) is defined as the ratio of milimoles per Liter of solution. 400mM means 400mmoles / L that is the same of <em>0,4mol / L</em>

100mL are <em>0,1L</em>. Using these values:

0,1L × (0,4mol / L ) = 0,04moles of indole-3-acetic acid.

As the MW of the molecule is 175,2 g/mol:

0,04mol × (175,2g / mol) = <em>7,01 g of indole-3-acetic acid</em>

<em></em>

Thus, <em>you need 7,01 g of indole-3-acetic acid to generate your solution</em>.

I hope it helps!

5 0
4 years ago
Use Q = mcAT
mr Goodwill [35]

Answer:

1).....for the specific heat capacity(c) of water is 4200kg/J°C..

....guven mass(m)=320g(0.32kg)

...change in temperature(ΔT) =35°C

from the formula

Q=mcΔT

Q=0.32Kg x 4200kg/J°C x 35°C

Q=47,040Joules

5 0
3 years ago
What amount of heat energy is required to raise the temperature of 152 g of water from 24 °C to 74 °C.
DIA [1.3K]

Answer:

Q = 31798.4J = 31.79kJ

Explanation:

Heat energy (Q) = ?

Mass (m) = 152g

T1 = 24°C

T2 = 74°C

Specific heat capacity of water (c) = 4.184J/g°C

Q = Mc∇T

Q = 152 * 4.184 * (74 - 24)

Q = 635.968 * 50

Q = 31798.4J

Q = 31.79kJ

Heat required is 31.79kJ

6 0
3 years ago
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