Left side:
Mg= 1
O= 2
H= 4
Cl= 2
Right side:
Mg= 1
O= 2
H= 4
Cl= 2
The reaction equation is first order with respect to [H+]
when PH1 = -㏒[H+]1 so, when PH = 6
So by substitution:
∴ 6 = -㏒[H+]1
∴[H+]1 = 1 x 10^-6
and when PH2 = -㏒[H+]2 so, when PH2 = 2
so by substitution:
∴ 2 = -㏒[H]2
∴[H]2 = 1 x 10^-2
So the rate of reaction changes by the factor of:
[H2]2/[H]1 = (1 x 10^-2) / (1 x 10^-6) = 10000
It is 10000 times faster when PH decreases from 6 to 2
Answer:
Hey mate.....
Explanation:
This is ur answer......
<em>While sunlight is the energy source, the greatest force propelling the water cycle is gravity. Gravity is the force of attraction between two objects, and Earth's gravity pulls matter downward, toward its center. It pulls precipitation down from clouds and pulls water downhill. Gravity also moves air and ocean water.</em>
Hope it helps!
mark me brainliest plz.....
Follow me!! :)
Answer:
The kinetic energy of the two curling stones is 320 J
Explanation:
Given;
mass of the first curling stone, m₁ = 20 kg
velocity of the first curling stone, v₁ = 4 m/s
velocity of the second curling stone, v₂ = - 4m/s
assuming the second curling stone to have equal mass with the first stone = 20 kg
The kinetic energy of the first curling stone is given by;
K.E₁ = ¹/₂m₁v₁²
K.E₁ = ¹/₂(20)(4)²
K.E₁ = 160 J
The kinetic energy of the second stone is given by;
K.E₂ = ¹/₂m₂v₂²
K.E₂ = ¹/₂ (20) (-4)²
K.E₂ = 160 J
Thus, the kinetic energy of the two curling stones is given by;
K.E = K.E₁ + K.E₂
K.E = 160 J + 160 J
K.E = 320 J
Therefore, the kinetic energy of the two curling stones is 320 J
