As a result, the greatest number of an atom's oxidation state will gradually rise over each period of the periodic table. For instance, the third period's highest value of the oxidation number will fall between 1 and 7.
- The Periodic Table only consistently varies the oxidation numbers of Group 1 and Group 2 metals in their compounds, which are always +1 and +2, respectively.
- Elements have an increasing number of valence electrons that can range from 1 to 8 and move from left to right over time. However, when H or O are added to an element first, the element's valency rises to 4, then falls to zero.
<h3>What causes a rise in the oxidation number?</h3>
An increase in oxidation number results from the loss of negatively charged electrons, whereas a reduction in oxidation number results from the gain of electrons. The result is a rise in the oxidation number of the oxidized element or ion.
<h3>Pattern of the Period 2?</h3>
The trends in Period 2 are significantly more clear-cut. All elements in period 2 experience a decrease in atomic radius, an increase in electronegativity, and an increase in ionization energy as their atomic number rises.
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D.The products will have at least 2 Na atoms and 1 O atom.
<h3>Further explanation
</h3>
Conservation of mass states that
<em>In a closed system, the masses before and after the reaction are the same
</em>
So it can be concluded
- mass of the reactants = mass of the products
- mass cannot be created or destroyed
- The number of atoms involved in a reaction remains the same⇒ number of moles also the same
- chemical equation in balanced form
So the number of atoms in reactants and products remains the same
Because one of the reactants in a reaction is Na₂O, so <em>The products will have at least 2 Na atoms and 1 O atom.</em>
Ksp - solubility product constant is equivalent to equilibrium constant, except this constant is used to determine the solubility of ions of a solid in a solution.
ksp is the product of the soluble ions in the compound. Higher the ksp value, higher the degree of solubility.
ZnCO₃ (s) ---> Zn²⁺ (aq) + CO₃²⁻ (aq)
n n
ksp = [Zn²⁺][CO₃²⁻]
In the equation equal amounts of ions Zn²⁺ and CO₃²⁻ ions are soluble.
amount of ions soluble = n
ksp is therefore equal to;
ksp = n x n
ksp = n²
ksp = 1 * 10⁻¹⁰ M
therefore
1 * 10⁻¹⁰ M = n²
n = 1 x 10⁻⁵ M
therefore concentration of CO₃²⁻ = 1 x 10⁻⁵ M
Yes. The two elements can combine to form different compounds.
<h3>Explanation</h3>
Two elements can combine at different ratios.
Consider CO and CO₂. Both are made from carbon and oxygen. However, C and O combine at a 1:1 ratio in CO but at a 1:2 ratio in CO₂. CO is a fuel; it burns in the air. CO₂ does not burn in the air; it is used to put out fires and is found in extinguishers. CO and CO₂ are two distinct compounds.
There are many ways for the elements to combine with each other. As a result, the first twenty elements on the periodic table alone can produce a large number of compounds.
