The answer to the question is letter 'C', water can be made to boil at 105 degrees Celsius by decreasing the air pressure on the water. Boiling occurs when the water is hot enough to have the same pressure as the surrounding air. at high altitudes the air pressure is lower than the sea level, it possible that the boiling of water can be raise until 105 degrees.
Answer:
Mass ratio: 71:112
Atomic ratio: 2:7
Explanation:
1. To get the mass ratio of of the compound Cl2O7, the following steps are followed:
- The atomic mass of Cl = 35.5g/mol, O = 16g/mol
- The mass of each element in the compound is as follows:
Cl2 = 35.5(2) = 71g
O7 = 16(7) = 112g
The mass ratio is the ratio of one mass of an element to another in the compound, hence, the mass ratio is 71:112
- The molar mass of the compound, Cl2O7, is determined:
71 + 112 = 183g/mol
- The mass percent of each element is determined by dividing the mass of each element present by the Molar Mass:
Cl = 71/183 = 0.3879 × 100 = 38.8%
O = 112/183 = 0.612 × 100 = 61.2%
2. Atomic ratio is the ratio of one atom in a molecule to another. It can be calculated this:
In Cl2O7, there are 9 total atoms (2 atoms of Cl + 7 atoms of oxygen).
Hence, that atomic ratio of Cl to oxygen in Cl2O7 is 2:7
The average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.
Given:
ΔH° of xenon difluoride (XeF2) = -105 kJ/mol
ΔH° of xenon tetrafluoride (XeF4)= -284 kJ/mol
ΔH° of xenon hexafluoride (XeF6) = -402 kJ/mol
The bond energy of Xe-F in XeF2 can be calculated as follows,
As we know that
ΔH° = ΔH°(bond formed) + ΔH°(bond broken)
The chemical reaction for the formation of XeF2 can be written in such a way,
Xe (g) + F2 (g) → XeF2 (g)
= [1 mol F2 (159 kJ/mol)] + [2(-Xe-F)] - 105 kJ/mol
= 159 kJ/mol + 2(-Xe-F) - 264 kJ/mol
= 2(-Xe-F)
Xe-F = 132 kJ/mol
Thus, we concluded that the average bond energy of the Xe¬F bonds in each fluoride is 132kJ/mol.
learn more about bond energy:
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2CH3COOH +Na2CO3 ----> 2CH3COONa + H20 + CO2
know you can find what all products formed from his reaction
