Answer: Apri
l is 17 and June is 10
Step-by-step explanation: I'm learning this in school
Perhaps you meant [(√(x^7))^(1/5)]^3
The fifth root of the square root of x to the seventh cubed?
√(x^7)=(x^7)^(1/2)=x^(7/2)
(x^(7/2))^(1/5)=x^(7/10)
(x^(7/10))^3
x^(21/10)
Sorry I did my best to decipher what you wanted to express.
In general:
(a^b)^c=a^(b*c) just work from the inside to the outside...
Cos θ = adj/hyp = 5/sqrt(5^2 + (-12)^2) = 5/sqrt(25 + 144) = 5/sqrt(169) = 5/13
2.79 in. Half of 1.48 is .64 and if you add them you come to 2.21 then subtract 2.21 from 5 and you get 2.79.
Hello
<span>an equation for the line in point-slope form and general form is :
y = ax+b a : </span>slope ; the <span>Passing through (x' ; y')
</span>y' = ax'+b
y-y' =a(x-x') and : x' =8 y' = -4
calculate a :
let : y = ax+b .....(D)
....(D') y = (1/5)x+4
.(D) perpendicular to(D') : slope (D) × slope (D') = -1
slope (D') = 1/5
slop(D)×(1/5) = -1
slope (D) = -5
equation for the line : y-y' =a(x-x')
y+4 =(-5) (x-8)
