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marin [14]
2 years ago
6

A pie is split into 3 equally sized

Mathematics
1 answer:
kenny6666 [7]2 years ago
3 0

the total area of the pie is 237

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Find the lateral area and surface area of a cone with a radius of 12 and a height of 21
marishachu [46]

Answer:

The Lateral Surface Area is 911.32 square unit and

Total Surface Area is 1361.7 square unit.

Step-by-step explanation:

For a given Cone

Radius (r) = 12

Height (h) = 21

<u>For Lateral Surface Area</u>

<h3><u>Formula</u><u>:</u> </h3>

A = πr√r² + h²

A = 3.14 × 12 × √(12)² + (21)²

A = 3.14 × 12 × √144 + 441

A = 3.14 × 12 × √585

A = 37.68 × 24.18

A = 911.32 square unit

Now,

<u>For</u><u> </u><u>Total</u><u> Surface Area</u>

<h3><u>Formula:</u></h3>

A = πrl + πr²

For Slant height (l)

l² = r² + h²

l² = (12)² + (21)²

l² = 144 + 441

l² = 585

l = 24.18

So,

A = πrl + πr²

A = πr(l + r)

A = 3.14 × 12 × (24.14 + 12)

A = 3.14 × 12 × 36.14

A = 1361.7 square unit

Thus, The <u>Lateral Surface Area</u> is 911.32 square unit and <u>T</u><u>otal Surface Area</u> is 1361.7 square unit.

<u>-TheUnknownScientist</u>

6 0
3 years ago
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A man is 37 years old and his child's age is 8. How many years ago was the product of their ages 96?
nexus9112 [7]

man is 37 years old and his child's age is 8. How many years ago was the product of their ages 96?

c0me g00.gle me.e. t

sub-mqgc-jtm

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5 0
3 years ago
HEEEEEEEEEEEEEEEEEEEEEEEEELLLLLLLLLLLLLLLLLLLLLLLPPPPPPPPPPPPPPP
zheka24 [161]
It is the third bubble
Hope i helped!
7 0
3 years ago
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Complementary and supplementary angles please answer please
kari74 [83]

Answer:

m<MON = 57

Hope this helps :)

3 0
2 years ago
I really need help and this answered ASAP. thank you and sorry.
Semenov [28]

9514 1404 393

Answer:

  $2.50

Step-by-step explanation:

The question asks for the total cost of a notebook and pen together. We don't need to find their individual costs in order to answer the question.

Sometimes we get bored solving systems of equations in the usual ways. For this question, let's try this.

The first equation has one more notebook than pens. The second equation has 4 more notebooks than pens. If we subtract 4 times the first equation from the second, we should have equal numbers of notebooks and pens.

  (8n +4p) -4(3n +2p) = (16.00) -4(6.50)

  -4n -4p = -10.00 . . . . . . . . . . . simplify

  n + p = -10.00/-4 = 2.50 . . . . divide by the coefficient of (n+p)

The total cost for one notebook and one pen is $2.50.

__

<em>Additional comment</em>

The first equation has 1 more notebook than 2 (n+p) combinations, telling us that a notebook costs $6.50 -2(2.50) = $1.50. Then the pen is $2.50 -1.50 = $1.00.

One could solve for the costs of a notebook (n) and a pen (p) individually, then add them together to answer the question. We judge that to be more work.

4 0
3 years ago
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