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3 years ago

What is the equation linear function in point-slope form M=-1/5 and f(0)=7

Mathematics

1 answer:

Scrat [10]3 years ago

7 0

Answer:

y-7= -1/5x

Step-by-step explanation:

general formula (y-y1)= m(x-x1)

m is the slope and in this case m=-1/5

(x1, y1) is a point on thhe line in this case is (0, 7) because f(x)=y

substitute your given in the equation

(y-7) = -1/5(x-0)

y-7= -1/5x

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Which fraction below represents a repeating decimal?

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Answer:

22/12

Step-by-step explanation:

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2 years ago

2.6.PS-

mojhsa [17]

Answer:

Step-by-step explanation:

5 bags= $12.50

1= ?

$12.50*1= 12.50

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2 years ago

The drama club sold bags of candy and cookies to raise money for the spring show. Bags of candy cost $5.50 and bags of cookies c

vaieri [72.5K]

Let's assume

the number of bags of candy =x

the number of bags of cookies =y

There were 5 more bags of cookies sold than candy

so, we get

$y=x+5$

Bags of candy cost $5.50

so, total cost of candy is

$=5.50x$

bags of cookies cost $3.50

so, total cost of cookies is

$=3.50y$

so,

total cost = (total cost of candy)+(total cost of cookies)

we get

total cost =5.50x+3.50y

so, we can plug

$5.50x+3.50y=53.50$

now, we can plug y

$5.50x+3.50(x+5)=53.50$

$5.5x\cdot \:10+3.5\left(x+5\right)\cdot \:10=53.5\cdot \:10$

$55x+35\left(x+5\right)=535$

$55x+35x+175=535$

$90x+175=535$

$90x+175-175=535-175$

$90x=360$

$x=4$

now, we can find y

$y=x+5$

$y=4+5$

$y=9$

so,

the number of bags of candy =4

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5 0

3 years ago

Instructions: Use the ratio of a 30-60-90 triangle to solve for the variables.

Pepsi [2]

Answer:

$x=20$

$y=10\,\sqrt{3}$

Step-by-step explanation:

In the triangle we have the following trigonometric equations:

$tan(60^o)=\frac{opposite}{adjacent} \\\sqrt{3} =\frac{y}{10} \\y=10\,\sqrt{3}$

and also:

$cos(60^o)=\frac{adjacent}{hypotenuse}\\\frac{1}{2} =\frac{10}{x}\\x=20$

8 0

3 years ago

find the local and/or absolute extrema for the function over the specified domain. (Order your answers from smallest to largest

Arlecino [84]

Answer:

Minimum 8 at x=0, Maximum value: 24 at x=4

Step-by-step explanation:

Retrieving data from the original question:

$f(x)=x^{2}+8\:over\:[-1,4]$

1) Calculating the first derivative

$f'(x)=2x$

2) Now, let's work to find the critical points

Set this

$2x=0\\x=0$

0, belongs to the interval. Plug it in the original function

$f(0)=(0)^2+8\\f(0)=8$

3) Making a table x, f(x) then compare

x| f(x)

-1 | f(-1)=9

0 | f(0)=8 Minimum

4 | f(4)=24 Maximum

4) The absolute maximum value is 24 at x=4 and the absolute minimum value is 8 at x=0.

5 0

3 years ago