3 years ago

Help please than you

Mathematics

1 answer:

____ [38]3 years ago

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Solve the simultaneous equations<br> 4x + 3y = 20<br> 4x + 2y = 14

fiasKO [112]

Step-by-step explanation:

$\underline{ \underline{ \text{Given}}} :$

$\tt{4x + 3y = 20........... \text{ equation \: ( \: i \: )}}$
$\tt{4x + 2y = 14.......... \text{equation \: (ii)}}$

$\underline{ \text{USE \: ELIMINATION \: METHOD}} :$

Subtract equation ( ii ) from equation ( i ) :

Remember that the sign of each term of the second expression changes i.e equation ( i ) now becomes -4x -3y = -20

$\tt{ \cancel{4x }+ 2y = 14}$

$\tt{ \cancel{ - 4x} - 3y = - 20}$

__________________

$\tt{ - y = - 6}$

⟿ $\tt{ \boxed{ \tt{y = 6}}}$

Again , Substituting the value of y in equation ( ii ) :

⟿ $\tt{4x + 2 \times 6 = 14}$

⟿ $\tt{4x + 12 = 14}$

⟿ $\tt{4x = 2}$

⟿ $\boxed{ \tt{x = \frac{1}{2}}}$

$\red{ \boxed{ \boxed{ \tt{Our \: final \: answer : x = \frac{1}{2 } \: and \: y = 6}}}}$

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