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Soloha48 [4]
3 years ago
8

Suppose you are given that p = 2q+1 and that p = 8.

Mathematics
1 answer:
iVinArrow [24]3 years ago
3 0

Answer:

We conclude that the following statements can be proved such as:

  • 2q+1 = 8    

Step-by-step explanation:

Given the expression

p = 2q+1

Given

p = 8

IF WE SUBSTITUTE p=2q+1 in p=8

Now, substituting p = 2q+1 in the expression p=8

p = 8

2q+1 = 8         ∵ p = 2q+1

Therefore, we conclude that the following statements can be proved such as:

  • 2q+1 = 8    
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How many solutions exist for the given equation?<br> 12x + 1 = 3(4x + 1) - 2
VladimirAG [237]

Answer:

Infinite

Step-by-step explanation:

3(4x + 1) - 2

= 12x + 3 - 2 (Multiply the sum in the bracket by 3)

= 12x + 1 (Simplify)

This means that:

12x + 1 = 3(4x + 1) - 2

is the same as

12x + 1 = 12x + 1

Hence, anything that is used to substitute x is correct.

4 0
3 years ago
A shop is having a sale all items are reduced work out the sale price of an item normally priced at £60
Naddik [55]

Question:

A shop is having a sales all items are reduced by 25%. Work out the sale price of an item normally priced at £60?

Answer:

The new price is £45

Step-by-step explanation:

Given

Sales\ price = \pounds 60

Rate = 25\%

First, calculate the reduction

Reduction = Rate * Sales\ price

Reduction = 25\% * \pounds 60

Reduction = \pounds 15

The new price is:

New = Sales\ price - Reduction

New = \pounds 60 - \pounds 15

New = \pounds 45

3 0
3 years ago
Which equation is y = (x + 3)2 + (x + 4)2 rewritten in vertex form? mc010-1.jpg mc010-2.jpg y = 2(x + 7)2 – 73 y = (x + 7)2 – 24
MArishka [77]
Y=(x+3)²+(x+4)²
y=x²+6x+9+x²+8x+16
y=2x²+14x+25
y=2(x²+7x+3.5²-3.5²)+25
y=2(x+3.5)²-2*3.5² +25
y=2(x+3.5)²+0.5
7 0
3 years ago
Read 2 more answers
Please help will give brainly
34kurt
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5 0
2 years ago
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Suppose the graph of a cubic polynomial function has the same zeroes and passes through the coordinate (0, –5).
Alexeev081 [22]
Zeros are the x values which make the function equal to zero. Set it up as you would for a binomial with a constant multiplier "k" to account for the y-intercept (0, -5) given.

f(x) = k(x-2)(x-3)(x-5)

Use the y-intercept (0,-5) to solve for k.

-5 = k(0-2)(0-3)(0-5)
-5 = -30k
-5/-30 = k
1/6 = k


The cubic polynomial function is then ..

f(x) = (1/6)(x-2)(x-3)(x-5)
 

Linear factors are the linear (line) expressions you can factor out of the polynomial. They are (x-2), (x-3) and (x-5).


5 0
3 years ago
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