All categories

2 years ago

Solve for X. x-9+2wx=y

Mathematics

1 answer:

iragen [17]2 years ago

5 0

Answer:

x=(y+9)/(1+2w)

Step-by-step explanation:

x-9+2wx=y

We make x the subject

x+2wx=y+9

x(1+2w)=y+9

Divide both sides by (1+2w)

x(1+2w)/(1+2w)=y+9(1+2w)

x=(y+9)/(1+2w)

You might be interested in

Marla did 65 sit-ups each day for one week.Use the distributive property to find out the number of sit-ups Marla did

xxMikexx [17]

All this question is asking you to do is multiply 65 and 7. The 7 comes from the amount of days in a week. The product of these numbers is 455.

Maria did 455 sit-ups in a week.

7 0

2 years ago

Read 2 more answers

!!!!!!! HELPPPPPP !!!!!! ASAP !!!!!!!!! HELPPPPPP!!!!!!!!!!!!

ElenaW [278]

Answer:

No you wouldn't because you are not dividing or multiplying by a negative number.

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

What is a dot product.

kifflom [539]

Answer:

In mathematics, the dot product or scalar product is an algebraic operation that takes two equal-length sequences of numbers (usually coordinate vectors), and returns a single number. ... Algebraically, the dot product is the sum of the products of the corresponding entries of the two sequences of numbers

kamsahamnida have a great day

7 0

2 years ago

Read 2 more answers

The perimeter of a Parallelogram is 72 meters.

Debora [2.8K]

Nice to know how long parallelogram is 72 meters :)

3 0

2 years ago

In the expansion (ax+by)^7, the coefficients of the first two terms are 128 and -224, respectively. Find the values of a and b

madam [21]

Answer:

a = 2, b = 3.5

Step-by-step explanation:

Expanding $(ax+by)^7$ using Binomial expansion, we have that:

$(ax+by)^7$ =

$(ax)^7(by)^0 + (ax)^6(by)^1 + (ax)^5(by)^2 + (ax)^4(by)^3 + (ax)^3(by)^4 + (ax)^2(by)^5 + (ax)^1(by)^6 + (ax)^0(by)^7$

$= (a)^7(x)^7+ (a)^6(x)^6(b)(y) + (a)^5(x)^5(b)^2(y)^2 + (a)^4(x)^4(b)^3(y)^3 + (a)^3(x)^3(b)^4(y)^4 + (a)^2(x)^2(b)^5(y)^5 + (a)(x)(b)^6(y)^6 + (b)^7(y)^7\\\\\\= (a)^7(x)^7+ (a)^6(b)(x)^6(y) + (a)^5(b)^2(x)^5(y)^2 + (a)^4(b)^3(x)^4(y)^3 + (a)^3(b)^4(x)^3(y)^4 + (a)^2(b)^5(x)^2(y)^5 + (a)(b)^6(x)(y)^6 + (b)^7(y)^7$