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Goryan [66]
3 years ago
15

Photo attached! 10 points! Thank you in advance!!

Mathematics
2 answers:
Fantom [35]3 years ago
6 0

ax^2+bx+c=0\\\\x^2+7x+9=3\qquad|\text{subtract 3 from both sides}\\\\x^2+7x+9-3=3-3\\\\\boxed{x^2+7x+6=0\to A.}

a=1,\ b=7,\ c=6

sleet_krkn [62]3 years ago
5 0

The answer is A because you subtract 3 from both sides to get the equation set to 0


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Bob's password consists of a non-negative single-digit number followed by a letter and another non-negative single-digit number
maw [93]

9/20 is the probability that Bob's password consists of an odd single-digit number followed by a letter and a positive single-digit number

It is given that bob's password consists of a non-negative single-digit number followed by a letter and another non-negative single-digit number (which could be the same as the first one).

P (odd single digit number )  =  ( 5 odd single digits / 10 non-negative single digits)  = (5/10)  = 1/2

P (positive single digit number ) =  (9 positive single digits / 10 non-negative single digits)  = 9/10

The total probability is   (1/2) (9/10)  =  9/20

Learn more about word problems here: brainly.com/question/21405634

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1 year ago
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Give a 98% confidence interval for one population mean, given asample of 28 data points with sample mean 30.0 and sample standar
klio [65]

We have a sample of 28 data points. The sample mean is 30.0 and the sample standard deviation is 2.40. The confidence level required is 98%. Then, we calculate α by:

\begin{gathered} 1-\alpha=0.98 \\ \alpha=0.02 \end{gathered}

The confidence interval for the population mean, given the sample mean μ and the sample standard deviation σ, can be calculated as:

CI(\mu)=\lbrack x-Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}},x+Z_{1-\frac{\alpha}{2}}\cdot\frac{\sigma}{\sqrt[]{n}}\rbrack

Where n is the sample size, and Z is the z-score for 1 - α/2. Using the known values:

CI(\mu)=\lbrack30.0-Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}},30.0+Z_{0.99}\cdot\frac{2.40}{\sqrt[]{28}}\rbrack

Where (from tables):

Z_{0.99}=2.33

Finally, the interval at 98% confidence level is:

CI(\mu)=\lbrack28.94,31.06\rbrack

4 0
1 year ago
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ICE Princess25 [194]

Answer:

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Step-by-step explanation: my assumption is that u r asking what 3% is. If u r then the answer above is correct bc 60 = 1% so multiply 60 by 3

If this is not what u r looking for please rephrase ur question

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oksano4ka [1.4K]
This is a lot of math to write.... so I'll just say the answer is -21 :D
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