Question

Photo attached! 10 points! Thank you in advance!!

Answer 1

$ax^2+bx+c=0\\\\x^2+7x+9=3\qquad|\text{subtract 3 from both sides}\\\\x^2+7x+9-3=3-3\\\\\boxed{x^2+7x+6=0\to A.}$

$a=1,\ b=7,\ c=6$

Answer 2

The answer is A because you subtract 3 from both sides to get the equation set to 0