3 years ago

Photo attached! 10 points! Thank you in advance!!

Mathematics

2 answers:

Fantom [35]3 years ago

6 0

$ax^2+bx+c=0\\\\x^2+7x+9=3\qquad|\text{subtract 3 from both sides}\\\\x^2+7x+9-3=3-3\\\\\boxed{x^2+7x+6=0\to A.}$

$a=1,\ b=7,\ c=6$

sleet_krkn [62]3 years ago

5 0

The answer is A because you subtract 3 from both sides to get the equation set to 0

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