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myrzilka [38]
3 years ago
15

PLS HELP ME

Mathematics
1 answer:
raketka [301]3 years ago
8 0

Answer:

y = 21°

Step-by-step explanation:

both are parallel lines, and that means

16x - 23 = 10x + 1

16x - 10x = 23 + 1

6x = 24

x = 4

---------------------------

taking 16x - 23

16 (4) - 23 = 64 - 23 = 41

both angles value is = 41°

------------------------------------

62° + x = 180

x = 180 - 62 = 118°

----------------------------------

the sum of all the angles inside the triangle is equal to 180°

41° + 118° + y = 180°

y = 21°

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It would take approximately 6.50 second for the cannonball to strike the ground.

Step-by-step explanation:

Consider the provided function.

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We need to find the time takes for the cannonball to strike the ground.

Substitute h(t) = 0 in above function.

-4.9t^2+30.5t+8.8=0

Multiply both sides by 10.

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For a quadratic equation of the form ax^2+bx+c=0 the solutions are: x_{1,\:2}=\frac{-b\pm \sqrt{b^2-4ac}}{2a}

Substitute a = -49, b = 305 and c=88

t=\frac{-305+\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}=-\frac{-305+\sqrt{110273}}{98}\\t = \frac{-305-\sqrt{305^2-4\left(-49\right)88}}{2\left(-49\right)}= \frac{305+\sqrt{110273}}{98}

Ignore the negative value of t as time can't be a negative number.

Thus,

t=\frac{305+\sqrt{110273}}{98}\approx6.50

Hence, it would take approximately 6.50 second for the cannonball to strike the ground.

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The net force in the forward direction will be 9 Newton.

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