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Lyrx [107]
3 years ago
13

{1.69} - \sqrt[3]{0.001} " alt=" \sqrt{1.69} - \sqrt[3]{0.001} " align="absmiddle" class="latex-formula">
​
Mathematics
1 answer:
Goshia [24]3 years ago
6 0

Given:

The expression is:

\sqrt{1.69}-\sqrt[3]{0.001}

To find:

The value of the given expression.

Solution:

We have,

\sqrt{1.69}-\sqrt[3]{0.001}

On simplification, we get

\sqrt{1.69}-\sqrt[3]{0.001}=1.3-0.1

\sqrt{1.69}-\sqrt[3]{0.001}=1.2

Therefore, the value of the given expression \sqrt{1.69}-\sqrt[3]{0.001} is 1.2.

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(2x+5)/(3x)-:(2x-1)/(x+1)
andreyandreev [35.5K]

Answer:

2x(power of two)+7x+5

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6x(power of two) -3x

Step-by-step explanation:

8 0
2 years ago
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Ben's employer will reimburse him $0.13 per mile driven. If Ben drives 210.1 miles on a business trip, what is his mileage reimb
Helen [10]

Answer:

27.31

Step-by-step explanation:

Take the number of miles and multiply by the reimbursement rate

210.1 * .13

27.313

Round to the nearest cent

27.31

5 0
2 years ago
Liz wants to buy her favorite musical group’s new CD. The CD costs $15.24, including tax. Liz gives the store clerk a twenty-dol
Mila [183]
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3 years ago
What value of x satisfies the equation 2x 5 − 3/5 = 4/5
kondor19780726 [428]
I hope this helps you

4 0
2 years ago
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A machine makes two components; call them types A and B. It takes 250 seconds to switch production between the component types.
Alexus [3.1K]

Answer:

The average inventory depends on the manufacturing batch size.

Its formula is:

Inventory=\frac{n}{3n+250}

Step-by-step explanation:

The question is incomplete.

Question complete:

<em>"A machine makes two components, call them type A and B. It takes 250 seconds to switch production between the component types. During that time no production occurs. When in production, each unit of A or B requires 0.5 seconds to be completed. The two components, A and B are combined in an assembly process to make a final product, call it C. The assembly step can combine the two components into 1 unit every 2 seconds. What is the average inventory of B components?"</em>

We have two steps in this process: the manufacturing of A and B and the assembly process.

We are not told about the batch size, so we will treat that as a variable called n. This represents the amount of units (of A or B) that are manufactured per cycle.

Time (seconds) to manufacture n units of A and n units of B:

T_m=n*0.5+n*0.5+250=n+250

Time (seconds)to assemble n units of C

T_a=n*2=2n

Then the total time of the cycle is:

T_m+T_a=n+250+2n=3n+250

The average inventory of B is n units per cycle, which lasts (3n+250) seconds.

Inventory=\frac{n}{3n+250}

For a batch size of 100 units, the average inventory is:

I_{100}=\frac{100}{3*100+250}=\frac{100}{550}=  0.182\, units/second

For a batch size of 1,000 units, the average inventory is:

I_{1000}=\frac{1000}{3*1000+250}=\frac{1000}{3250}=  0.308\, units/second

5 0
3 years ago
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