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3 years ago

Suppose Reggie runs 4 laps around the track in the same time that Kyle runs 3.5 laps.

Mathematics

1 answer:

Marta_Voda [28]3 years ago

4 0

Answer:

sadsda

Step-by-step explanation:

asdasdadasddas

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Can someone please answer. There is a picture. It is only one question. Thank you so much!

Charra [1.4K]

We can check each of these using the Pythagorean Theorem, $a^2 + b^2 = c^2$
Option A:
$.5^2 + 1.2^2 = 1.3^2

$
.25 + 1.44 = 1.691.69 = 1.69
This option works
Option B
$1^2 + 2^2 = 3^2$
1 + 4 = 9
5 ≠ 9
This option does not work, but let's check the others to make sure
Option C:
$6^2 + 8^2 = 10^2$
36 + 64 = 100
100 = 100
This option works
Option D:
$3^2 + 4^2 = 5^2$
9 + 16 = 25
25 = 25
This option works

So, after doing the calculations, we see that option B does not work

6 0

3 years ago

Pls helpppppppp!!!!!!!!!!!!!!!!!!!!<br><br>I'll award brainliest

kolezko [41]

Answer:

I swear i had the exact same problem

Step-by-step explanation:

826 1/25

6 0

3 years ago

Read 2 more answers

What is the volume of the cone below?

lara [203]

Answer:

the world may never know

Step-by-step explanation:

7 0

4 years ago

In the coordinate plane, the point A, 4− 2 is translated to the point A′, 1− 5. Under the same translation, the points B, 7− 4 a

Inga [223]

Answer:

The coordinates of B' and C' are $B'(x,y) = (4, -7)$ and $C'(x,y) = (-1, -8)$ , respectively.

Step-by-step explanation:

From the Linear Algebra, we define the translation of a given point as:

$O'(x,y) = O(x,y) + T(x,y)$ (1)

Where:

$O(x,y)$ - Original point, dimensionless.

$T(x,y)$ - Translation vector, dimensionless.

$O'(x,y)$ - Translated point, dimensionless.

If we know that $A'(x,y) = (1, -5)$ and $A(x,y) = (4,-2)$ , then the translation vector is:

$T(x,y) = A'(x,y)-A(x,y)$ (2)

$T(x,y) = (1,-5)-(4,-2)$

$T(x,y) = (-3,-3)$

If we know that $B(x,y) = (7,-4)$ , $C(x,y) = (2,-5)$ and $T(x,y) = (-3,-3)$ , then the translated points are, respectively:

$B'(x,y) = B(x,y)+T(x,y)$ (3)

$B'(x,y) = (7,-4) +(-3,-3)$

$B'(x,y) = (4, -7)$

$C'(x,y) = C(x,y) +T(x,y)$

$C'(x,y) = (2,-5) + (-3,-3)$

$C'(x,y) = (-1, -8)$

The coordinates of B' and C' are $B'(x,y) = (4, -7)$ and $C'(x,y) = (-1, -8)$ , respectively.

5 0

3 years ago

Pls help I’ve already tried 3/11 but it says it wrong

love history [14]

Answer:

Step-by-step explanation:

Alr so correct me if I'm wrong but I think you made a mistake. It says find 44 of those rectangles. You found just 1 in that case which the area is 3/11. You have to do 3/11 X 44 which is

3/11 x 44/1 = 132/11 = 12.

As I said, correct me if I'm wrong.

Hope this Helps!

5 0

3 years ago